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UNO [17]
3 years ago
12

a spinner is divied into 8 equal sections,and each section contains a number from 1 to 8.what is the probabilaty of the spinner

landing on 5
Mathematics
2 answers:
mixas84 [53]3 years ago
7 0
Well since there are eight sections of 1-8 that meanst there are 8 different number 5s, and since there are eight sections of 8 it becomes 64, so if my math is correct 8/64ths of the time or 1/8. It might be wrong but I tried.
Talja [164]3 years ago
3 0
Possible outcomes (sample space) = {1,2,3,4,5,6,7,8}
Number of outcomes, n = 8
Probability of landing on 5
= 1 outcome / n outcomes
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Ilia_Sergeevich [38]

Answer:

x = 20

Step-by-step explanation:

These angles are vertical angles.

Vertical angles are congruent!! So we set them equal to one another.

2 + 3x = 62

-2           -2

3x = 60

----    ---

3       3

x = 20

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2 years ago
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the distance between nick and sara's house is 546m. Nick can walk 1.3m/sec. using the formula d=rt, where d is distance, r is ra
Paraphin [41]
Rearrange the formula to solve for time. Which is the distance over the rate. Then divide 546 meters by 1.3 meters per second. The meter units cancel each other out leaving you with : t: 420.
7 0
3 years ago
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Write the sentence as an equation.<br> 143 more than the product of g and 369 is equal to 141.
DiKsa [7]

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143>(369g=141)

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3 years ago
You roll a six-sided number cube and flip a coin. What is the probability of rolling a number less than 2 and flipping heads? *
leonid [27]

Answer:

1/12

Step-by-step explanation:

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Then, you will note that a coin only has 2 sides, so there is a 50/50 chance of getting heads, or 50%. Now, you will turn that into a fraction, which is 1/2.

Next, you will multiply to make the denominators the same. And what you do to the denominator must happen to the numerator. (1/6 * 2--> 1/12 and 1/2 * 6 = 1/12)

Hope this helps! :)

7 0
3 years ago
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Given the function how do I solve
BARSIC [14]

Answer: (a) -7      (b) \bold{\dfrac{4}{25}}      (c) \bold{-\dfrac{5}{2}}    (d) 4

Step-by-step explanation:

A) f(x) = 2x - 3      when x is between -5 and -2 (including -5 and -2)

B) f(x) = x²            when x is between -2 and 2 (including 2)

C) f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}             when x is between 2 and 5 (including 5)

a) Equation A includes x = -2

   f(x) = 2x - 3

   f(-2) = 2(-2) - 3

           =  -4    - 3

           =       -7

b) Equation B includes x = -\dfrac{2}{5}

   f(x) = x²

   f\bigg(-\dfrac{2}{5}\bigg) = \bigg(-\dfrac{2}{5}\bigg)^2

        =\dfrac{4}{25}

c) Equation C includes x = 4

   f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}

   f(4)=-\dfrac{3}{2}(4)+\dfrac{7}{2}

       =-\dfrac{12}{2}+\dfrac{7}{2}

       =-\dfrac{5}{2}

d) Try each equation to see if x falls within the values given.

A) f(x) = 2x - 3

   -2.5 = 2x - 3

    0.5 = 2x

  0.25 = x    NOT VALID since x should be between -5 and -2

B) f(x) = x²

   -2.5 = x²

   \sqrt{-2.5}=x  NOT VALID since x cannot be an imaginary number

C) f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}

    -\dfrac{5}{2}=-\dfrac{3}{2}x+\dfrac{7}{2}

    -\dfrac{12}{2}=-\dfrac{3}{2}x

    -\dfrac{12}{2}\bigg(\dfrac{2}{3}\bigg)=x

    4 = x        VALID since x is between 2 and 5

5 0
4 years ago
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