The nucleus contains the genetic material of an eukaryotic cell.
Given:
The function are
To find:
The value of 
.
Solution:
We have,
We need to find the value of .
![[\because (f\circ g)(x)=f(g(x))]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28f%5Ccirc%20g%29%28x%29%3Df%28g%28x%29%29%5D)
![[\because g(x)=\sqrt{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3D%5Csqrt%7Bx%7D%5D)
![[\because f(x)=x^2-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20f%28x%29%3Dx%5E2-1%5D)
The value of is 0.
Therefore, the correct option is A.
Answer:
382 cm²
Step-by-step explanation:
Front face + Back face:
A = 2(a + b)h/2
A = 2(14 cm + 8 cm)(7 cm)/2
A = 154 cm²
Left face:
A = 7 cm × 6 cm = 42 cm²
Right face:
A = 9 cm × 6 cm = 54 cm²
Bottom face:
A = 14 cm × 6 cm = 84 cm²
Top face:
A = 6 cm × 8 cm = 48 cm²
Total surface area =
= (154 + 42 + 54 + 84 + 40) cm²
= 382 cm²
184,000 can be rounded by underlining the 3 in the thousands place and look to the right. if, it is more than 5 add 1 to the left, 184.... then replace the numbers behind the rounded number, will be 0. 184,000
<span />
Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
