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Reptile [31]
3 years ago
14

Me.Durham is contemplating which chauffeured car service to the airport. The first costs $30 up front and $3 per kilometer. The

second costs $20 plus $5 per kilometer. For a certain driving distance, the two companies charge the same total fare. What is the total fare?
Mathematics
1 answer:
Semmy [17]3 years ago
8 0

Answer: 45 dollars and it was a distance of 5 kilometers

Step-by-step explanation: What i did was start with 30, then keep adding 3 till i got the a multiple of 5.

30 + 3 = 33

33 + 3 = 36

36 + 3 = 39

39 + 3 = 42

42 + 3 = 45

So already i know that it is 5 kilometers, because i added 3 to 30 five times.

No i will do that with the second company

20 + 5 = 25

25 + 5 = 30

30 + 5 = 35

35 + 5 =  40

40 + 5 = 45

That is also 5 kilometers, because i added 5 to 20 five times. I also know they are the same price, because they both added to 45 dollars.

Thats how i solved it.

I really hope that helps!

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Vesnalui [34]

Answer:

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Step-by-step explanation:

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3 years ago
I need help ASAP <br> 120&gt;10n+20
Burka [1]

Answer:n = 10 can make the inequality true

Step-by-step explanation:

The given inequality is

120 greater than or equal to 10n + 20. This means that the least value of n that would make the inequality true would be 10.

If we substitute n = 10 into the right hand side of the given inequality, it would result to 120.

So n = 10 can make the inequality true.

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3 years ago
Clue #1: The sum of the digits of a 3 digit number is 20. Clue #2: The tens digit is 2 less than the hundreds digit. Clue #3: Th
o-na [289]

Answer: The number is 974

Step-by-step explanation:

First, any 3 digit number can be written as:

N = a*100 + b*10 + c

Where a, b, and c are single-digit numbers.

a is the hundreds digit

b is the tens digit

c is the unit digit

We can write the clues as:

#1: a + b + c = 20

#2: b = a - 2

#3: c = a + b - 12

Then we have a system of equations:

a + b + c = 20

b = a - 2

c = a + b - 12

To solve this, we need to isolate one of the variables in one equation and then replace this in the other equations, we can see that b is already isolated in the second equation, then we can replace that in the first and third equations:

a + (a - 2) + c = 20

c = a + (a - 2) - 12

Now we can see that c is isolated in the second equation, then we can replace that in the first one to get:

a + (a - 2) + (a + (a - 2) - 12) = 20

Now we can solve this for a:

a + a - 2 + a + a -2 - 12 = 20

4*a - 16 = 20

4*a = 20 + 16

4*a = 36

a = 36/4 = 9

With this, we can find the values of b and c.

b = a - 2 = 9 - 2 = 7

c = a + b - 12 = 9 + 7 - 12 = 4

Then the 3-digit number is:

N = a*100 + b*10 + c = 9*100 + 7*10 + 4 = 974

N = 974

6 0
3 years ago
The polynomial equation x^3-4x^2+2x+10=x^2-5x-3 has complex roots 3+-2i What is the other root? Use a graphing calculator and a
kirill115 [55]

Answer:

B. -1

Step-by-step explanation:

x^3-4x^2+2x+10=x^2-5x-3

We know it has 3 roots since it is a 3rd degree polynomial.

Two of the roots are (3+2i) and (3-2i)

Subtract x^2-5x-3 from both sides

x^3-4x^2+2x+10-(x^2-5x-3)=x^2-5x-3 -(x^2-5x-3)

Distribute the minus sign

x^3-4x^2+2x+10-x^2+5x+3=x^2-5x-3 -x^2+5x+3

x^3 -5x^2+7x +13 =0

Graphing this equation , we see that it crosses the x axis at x=-1

That covers the three roots, 1 real and two complex

7 0
3 years ago
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