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Reptile [31]
3 years ago
14

Me.Durham is contemplating which chauffeured car service to the airport. The first costs $30 up front and $3 per kilometer. The

second costs $20 plus $5 per kilometer. For a certain driving distance, the two companies charge the same total fare. What is the total fare?
Mathematics
1 answer:
Semmy [17]3 years ago
8 0

Answer: 45 dollars and it was a distance of 5 kilometers

Step-by-step explanation: What i did was start with 30, then keep adding 3 till i got the a multiple of 5.

30 + 3 = 33

33 + 3 = 36

36 + 3 = 39

39 + 3 = 42

42 + 3 = 45

So already i know that it is 5 kilometers, because i added 3 to 30 five times.

No i will do that with the second company

20 + 5 = 25

25 + 5 = 30

30 + 5 = 35

35 + 5 =  40

40 + 5 = 45

That is also 5 kilometers, because i added 5 to 20 five times. I also know they are the same price, because they both added to 45 dollars.

Thats how i solved it.

I really hope that helps!

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Please answer question
sweet-ann [11.9K]

Given;

ABCDE is similar to VWXYZ

so, the corresponding segments are proportional

We need to find the length of XY

XY is corresponding to CD

CD = 1.2 cm

Finding another two corresponding sides

DE = 3.2 cm , YZ = 4 cm

so,

\begin{gathered} \frac{XY}{CD}=\frac{YZ}{DE} \\  \\ \frac{XY}{1.2}=\frac{4}{3.2} \\  \\ XY=\frac{4}{3.2}\cdot1.2=1.5\operatorname{cm} \end{gathered}

So, the length of XY = 1.5 cm

3 0
1 year ago
Draw 2 cards from a standard deck of 52 cards. What is the probability that the first card is a queen and the second card is a k
bixtya [17]

Answer:

4/663

Step-by-step explanation:

There are four queens.  The probability that the first card is a queen is 4/52.

There are four kings.  There are 51 cards left after the first card has been drawn, so the probability that the second card is a king is 4/51.

Therefore, the probability that the first card is a queen AND the second card is a king is:

P = 4/52 × 4/51

P = 4/663

3 0
3 years ago
Can I please have the answers.
Brums [2.3K]

Question 22.). Write the equation in Standard Form:

10y = 12x + 0.7

Identify: A, B, C

Standard Form for Linear Equation: Ax + By = C

10y = 12x + 0.7

The Standard Form of the solution is

Ax + By = C, Where, A ≥ 0

A and B, are Non- Zero numbers.

Therefore, Your answer, Letter Choice, (D), 120x - 100y = - 7, Where,

A = 120, B = - 100, and C = - 7

Question 24.). Described as, Inconsistent, Consistent, and Independent, Consistent, and Dependent, or None of These.

9x - 8y = 15, and 27x - 24y = 3

Solve:

9x - 8y = 15; 27x - 24y = 3

Steps: I will try to solve the system of equation:

9x - 8y = 15; 27x - 24y = 3

Step, Solve: 9x - 8y = 15 for x

9x - 8y + 8y = 15 + 8y

Add 8y to both sides:

9x = 8y + 15

9x/9 = 8y + 15/9 ( Divide both sides by 9):

x = 8/9y + 5/3

Step Substitute:

8/9y + 5/3 for X in 27x - 24y = 3

27x - 24y = 3

27 ( 8/9y + 5/3) - 24y = 3

45 = 3

Simplify Both sides of equation:

45 + - 45 = 3 + - 45 ( Add - 45, to both sides.):

0 = - 42

Therefore, No real Solutions, to both Equation.

Hence; 9x - 8y = 15; and 27x - 24 = 3, have No Real Solutions, and Therefore, They are, Answer Letter Choice, (B), Inconsistent.

Hope that helps!!! Sorry, I couldn't figure out Number (23.). : )

8 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
Carol opened 20 different bags of the same kind of candy and recorded the colors and their frequencies, as shown in the table.
Alina [70]
It is 14% as you add up all of the numbers and divide 10 by that number and finally multiply by 100 for a percent
7 0
3 years ago
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