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2 years ago

6

Why do teachers give out so much homework? I can understand why colledge and hugh school get it, but why the younger ones? They'

re still delevoping. Why? (This doesn't have to do with any subjects; it's not math)...

1 answer:

seraphim [82]2 years ago

8 0

Most teachers say that they do it to make sure the kids dont't forget what ws tought that day or to review

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The pyramid shown has a square base that is 18 inches on each side. The slant height is 16 inches. What is the surface area of t

Alik [6]

The answer is 28sqinches Why The Surface Area of a pyramid is A=L×W×Have since the base is l×with combined it's now SA=BA×H
SA=18×16
SA=288sqinches.

4 0

2 years ago

Can someone plz help me with this one problem plzzzzz <br><br> (I’M MARKING BRAINLIEST)

Andre45 [30]

In order from top to bottom, 2,8,14,20
And it’s the second graph (right)

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3 years ago

Sin(42) = cos(x) <br> Solve for x

mariarad [96]

Answer:

X = 48

Step-by-step explanation:

When you type sin(42) in your calculator it will give you something around 0.669.

If you try reverse sinus sin-1(0.669) it will give you 42.

Therefore you can say that:

Cos(x) = 0.669

So you can reverse the cos to get your answer

Cos-1(0.669) = 48

Or

Cos-1 (sin(42))

3 0

3 years ago

y is inversely proptional to x when y = 7, x = 9 a) work out an equation connecting y and x b) work out the value of y when x =

OLga [1]

Answer:

a) yx=63

b) y=3

Step-by-step explanation:

a)

yx=k (inverse formula)

7(9)=k

63=k

b)

y(21)=63

y=63/21

y=3

3 0

2 years ago

il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3

Thus, the required value of the s = -16/3. None of these are correct.

Learn more about simplification here: brainly.com/question/12501526

#SPJ1

4 0

1 year ago