241.402 kilometers
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Answer:
QR = 5.
Step-by-step explanation:
Because the parallelograms are similar then the corresponding sides are in the same ratio.
So AB / PQ = BC / QR
9/3 = 15 / QR
15 / QR = 3
QR = 15/3
= 5. (answer)
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
The area that the dog can wander based on the information provided will be 931π.
<h3>How to calculate the area?</h3>
From the information, we are told that the dog dog is attached to a 35-foot rope fastened to the outside corner of a fenced-in garden that measures 28 feet by 36 feet.
In this case, the dog is in an outside corner. The dog can trace 3/4 of a circle when it starts walking in a circle away form the wall.
The area that the dog can wander will be:
= 3/4(π35²) + 1/4(π(35 - 28)²)
= 3/4π(35)² + 1/4π(7)²
= (3/4 × 1225)π + (1/4 × 49)π
= 918.75π + 12.25π
= 931π
Therefore, the area that the dog can wander based on the information provided will be 931π.
Learn more about area on:
brainly.com/question/25292087
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