Question

Ms. Garza invested $50,000 in three different accounts. She invested three times as

Answer 1

Answer:

The amount invested in the account that paid 8%  was $18,000

The amount invested in the account that paid 10%  was $6,000

The amount invested in the account that paid 12%  was $26,000

Step-by-step explanation:

Let

3x -----> the amount invested in the account that paid 8%

x -----> the amount invested in the account that paid 10%

$50,000-4x ----> the amount invested in the account that paid 12%

in this problem we have

$8\%=8/100=0.08\\10\%=10/100=0.10\\12\%=12/100=0.12$

we know that

$3x(0.08)+x(0.10)+(50,000-4x)(0.12)=5,160$

Solve for x

$0.24x+0.10x+6,000-0.48x=5,160$

$0.48x-0.24x-0.10x=6,000-5,160$

$0.14x=840$

$x=\ 6,000$

$3x=\ 18,000$

$\ 50,000-4x=\ 26,000$

therefore

The amount invested in the account that paid 8%  was $18,000

The amount invested in the account that paid 10%  was $6,000

The amount invested in the account that paid 12%  was $26,000