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4 years ago

14

Write a quadratic function in standard form having zeros of -9 and -12

1 answer:

tia_tia [17]4 years ago

3 0

(x + 9)(x + 12) = 0
Expanding the brackets, we get:
$x^{2}+21x+108=0$

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Score: 0 of 1 pt

jonny [76]

Answer:

See attachment for graph

Step-by-step explanation:

Given

$y = x^2 - 3$

Required

The graph of the equation

First, we determine the range of y

$x = -3$

$y = x^2 - 3 \to y = (-3)^2 - 3 = 6$

$(-3,6)$

$x = -2$

$y = (-2)^2 - 3 = 1$

$(-2,1)$

$x = -1$

$y = (-1)^2 - 3 = -2$

$(-1,-2)$

$x=0$

$y = 0^2 - 3 = -3$

$(0,-3)$

$x = 1$

$y= 1^2 - 3 = -2$

$(1,-2)$

$x = 2$

$y =2^2 - 3 = 1$

$(2,1)$

$x = 3$

$y = 3^2 - 3 = 6$

$(3,6)$

<em>See attachment for graph</em>

7 0

3 years ago

Guys do you know this question?

jeka94

The picture wouldn’t load for me.. :(

5 0

3 years ago

anyanavicka [17]

The axis of symmetry is x=2.

6 0

3 years ago

Find two consecutive whole numbers such that the sum of their squares is 421

ruslelena [56]

The equation you would need to solve is <span><span>x^2</span>+(x+1<span>)^2</span>=421. I'm not at a college level though so i don't know how to.

Give me feedback if this helped!</span>

3 0

3 years ago

Find the equation of the line perpendicular to x−5y=15 that passes through the point (−2,5).

defon

Answer:

Step-by-step explanation:

-5y = -x + 15

5y = x - 15

y = 1/5x - 3

perp. -5

y - 5 = -5(x + 2)

y - 5 = -5x - 10

y = -5x - 5

7 0

3 years ago