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Tpy6a [65]
3 years ago
13

Find the distance between the points L(7,-1) and M(-2, 4).

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

The answer is

\sqrt{106}  \:  \:  \: or \:  \:  \: 10.3 \:  \:  \:  \: units

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

L(7,-1) and M(-2, 4)

The distance between them is

|LM|  =   \sqrt{ ({7 + 2})^{2}  + ( { - 1 - 4})^{2} }  \\  =  \sqrt{ {9}^{2}  +  ({ - 5})^{2} }  \\  =  \sqrt{81 + 25}  \\  =  \sqrt{106}  \:  \:  \:  \:  \:  \:  \:  \\  = 10.29563014...

We have the final answer as

\sqrt{106}  \:  \:  \: or \:  \:  \: 10.3 \:  \:  \:  \: units

Hope this helps you

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The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And the confidence interval is given by:

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And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

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\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And the confidence interval is given by:

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And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

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