Ohh wow nice, do your own work lazy person
We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2
the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14
</span>
Answer:
the burgers be 3 and fries be 2
Step-by-step explanation:
The computation is shown below:
Let us assume burgers be x
And, the fries be y
Now according to the questiojn
1.25x + 0.50y = $4.75
1.50x + 0.99y = $6.48
Now multiply by 1.2 in the first equation
1.50x + 0.6y = $5.70
1.50x + 0.99y = $6.48
-0.39y = -0.78
y = 2
Now put the value of y in any of the above equation
1.25x + 0.50(2) = $4.75
x = 3
Hence, the burgers be 3 and fries be 2
