The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If
m is the mean number of customers serviced in an hour, then P=1-e^mt
1 answer:
Answer: option d.
Step-by-step explanation:
You have the following formul given in the problem:
You know that:
The number of customers serviced in an hour by the technical support representative is 6 costumbers, therefore:
As the problem asked for the probability that a costumber will be on hold less than 30 minutes, we know that:
Substitute the values above into the formula.
Then, you obtain:
or 95%
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