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Ganezh [65]
3 years ago
10

The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If

m is the mean number of customers serviced in an hour, then P=1-e^mt

Mathematics
1 answer:
Molodets [167]3 years ago
7 0

Answer: option d.

Step-by-step explanation:

You have the following formul given in the problem:

p=1-e^{-mt}

You know that:

The number of  customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

m=6

As the problem asked for the probability that  a costumber will be on hold less than 30 minutes, we know that:

t=0.5

Substitute the values above into the formula.

Then, you obtain:

p=1-e^{-(6)(0.5)}=0.95 or 95%

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