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Misha Larkins [42]
3 years ago
13

A triangular bandana has an area of 78 square inches. The height of the triangle is 9

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0
Area of a triangle = 1/2 × base × height

Plug in what we know.

78 = 1/2 × b × 9¾

Multilply each side by 2 to get rid of the 1/2...

156 = b × 9¾

Write 9¾ as an improper fraction.
(9¾ = 9 + 3/4 = (9×4)/4 + 3/4 = 36/4 + 3/4 = 39/4)

156 = b × 39/4

Multiply each side by 4...

624 = b × 39

Divide each side by 39...

16 = b

Done! The length of the base of the triangle is <u>16</u> inches.
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Can I get some help on this math problem
pogonyaev

Answer:

x=3\sqrt{5}

Step-by-step explanation:

<u>Right Triangles</u>

Right triangles have one of its interior angles with a measure of 90°.

In right triangles the Pythagora's Theorem is satisfied.

Being c the longest side (hypotenuse), a and b the shorter sides (the legs), then:

c^2=a^2+b^2

We have modified the image to include some known data. Both triangles are congruent since they share one side, have a right angle, and have the same base length.

This means the value of x can be calculated as the hypotenuse of the triangle 3-6-x:

x^2=3^2+6^2=9+36=45

x=\sqrt{45}=\sqrt{9*5}

\boxed{x=3\sqrt{5}}

4 0
3 years ago
You’ve analyzed each game. Which game earns you more points?
tatiyna

Answer:

Game 2

Step-by-step explanation:

Each hit the points would double (point(x2))

Example:

1x2=2, 2x2=4, 4x2=8, 8x2= 16, 16x2=32, and so on.

7 0
3 years ago
Read 2 more answers
(16 divided by 4) x (7-4)
zavuch27 [327]
4 x 3 = 12
12 would be the answer
4 0
3 years ago
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3x/2 = 5<br><br><br> What's x????
Anni [7]
\frac{3x}{2} = 5
taking 2 to the other side ⇒ \frac{3x}{} = 5 x 2 
3x=10
taking 3 to the other side ⇒ x = \frac{10}{3}
 x = 3.34
3 0
4 years ago
Read 2 more answers
How many gallons of a 50% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 40% antif
Mariulka [41]

I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.

Let <em>x</em> be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (<em>x</em> + 60) gal.

Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.

We want the concentration of antifreeze to be 40% in the new solution, so we need to have

(0.5 <em>x</em> + 18) / (<em>x</em> + 60) = 0.4

Solve for <em>x</em> :

0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)

0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24

0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18

0.1 <em>x</em> = 6

<em>x</em> = 6/0.1 = 60 gal

6 0
4 years ago
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