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Monica [59]
3 years ago
15

Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Wr

ite an inequality that would be used to solve for the least amount of money he needs to deposit to avoid a fee. A. 727.29 + 248.50 − x ≥ 500 B. 727.29 + 248.50 − x ≤ 500 C. 727.29 − 248.50 + x ≥ 500 D. 727.29 − 248.50 − x ≤ 500
Mathematics
1 answer:
MissTica3 years ago
6 0

Answer:

inequality is

727.29-248.50+x>500

x=how much she needs to deposit

478.79+x>500

subtract 478.79 from both sides

x>21.21

at least $21.21

Step-by-step explanation:

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A climber on Mt Everest is 6000 meters from the start of his trail and at elevation 8000 meters above sea level. At x meters fro
sergeinik [125]

Answer:

h'(x) = 0.6 and Δx = 1 and 2

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Explanation below:

Step-by-step explanation:

Based on the information given we have that when the climber is 6000 meters from the start, his elevation is 8000 meters above sea level.

We know that the function for elevation is given by h(x) where x is the number of meters from the start.

Therefore, h(6000) = 8000.

We also know that the derivative of a function tells us the reason of change at some point (or how fast a function is changing near that point). For this problem we have that h'(x) = 0.6. (<u>meaning that the elevation increases in 0.6 meters for every meter they hike further nearby the 6000 meters</u>)

We need to use the derivative at a point to estimate values of the function at nearby points

We're going to use h'(x)= 0.6. Δx= 1

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

Therefore h (6001) = 8,000.6

Now for h'(x)= 0.6. Δx= 1

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Therefore h(6002) = 8001.2

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3 years ago
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
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Complete this sequence 4.15, 6.3, 8.45
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+2.15.
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2 years ago
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5. If W(-10, 4), X(-3,-1), and Y(-5, 11) classify AWXY by its sides. Show all work to justify your
Ierofanga [76]

Answer:

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Step-by-step explanation:

The square of the length of a side can be found from the distance formula:

  d^2 = (x2-x1)^2 +(y2-y1)^2

The square of the length of WX is ...

  WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74

The square of the length of XY is ...

  XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148

The square of the length of YW is ...

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The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.

3 0
3 years ago
HELP ME PLEASE!!!!!!
gladu [14]

Answer:

6x²y²

Step-by-step explanation:

6: 1 2 3 6

18: 1 2 3 6 9 18

36: 1 2 3 4 6 9 12 18 36

the common factor for 6 18 and 36 are

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x² = x × x

y³ = y × y × y

x³ = x × x × x

y³ = y × y × y

x³ = x × x × x

y² = y × y

the common factor are for x and y are

x² y²

Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²

5 0
2 years ago
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