Question

Plz help me!!!!!!!!!!

Answer 1

Answer:  $\bold{\dfrac{5\pm \sqrt{57}}{4}}$

Step-by-step explanation:$2a-5=\dfrac{4}{a}\\\\\text{Multiply by the LCD (a) to clear the denominator:}\\\\\\2a(a)-5(a)=\dfrac{4}{a}(a)\\\\2a^2-5a=4\\\\2a^2-5a-4=0\quad \rightarrow \quad a=2,\ b=-5,\ c=-4\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(2)(-4)}}{2(2)}\\\\\\.\ =\dfrac{5\pm \sqrt{25+32}}{4}\\\\\\.\ =\dfrac{5\pm \sqrt{57}}{4}$

Answer 2

Answer:

a = ( 5 +/- sqrt(57) )/2

Step-by-step explanation:

Uh...well just multiply by a and move the 4, setting the equation to 0.

a, b, and c are 2, -5, -4

Plug that into the QuadF.