4 years ago

The function f is defined by f(X)=x^2-6x+21

Mathematics

1 answer:

dem82 [27]4 years ago

3 0

The answer i got is in the image below

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James is pulling toys out of his toy box, either 2 at a time, 3 at a time, or 4 at a time. In how many ways, including order, ca

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Step-by-step explanation:

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3 years ago

after a party, there are parts of three pizzas remaining. There is a 1/5 of a pepperoni pizza remaining, 3/8 of a cheese pizza r

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2/5

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3 years ago

Simon bought a 48$ dollar table on sale for 30 percent off

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3 years ago

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Dont you have to have the beginning amount of water?

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Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

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3 years ago