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Sidana [21]
3 years ago
12

Can someone help me with all of this plz

Mathematics
1 answer:
zlopas [31]3 years ago
4 0
Here's a solution for #8
Volume of a sphere = V = 4/3π r³
Your radius r = 6, so plugging that in you get:
V = 4/3π(6³)
V = 4/3π216
V = 864/3π
V = 288π (units³)

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Answer: BCD

Step-by-step explanation:

A is incorrect since there is no angle Y to exist

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Answer for this question
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This isnt about math but. Why do some people keep talking about fairys and using this emoji ‍♀️
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With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en
mrs_skeptik [129]

Answer:

0.9167 = 91.67% probability that the entire batch will be accepted

Step-by-step explanation:

The CDs are chosen without replacement, which means that the hypergeometric distribution is used.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

2100 write-rewrite CDs, and 60 are defective.

This means, respectively, that N = 2100, k = 60

3 of these CDs are randomly selected for testing

This means that n = 3

What is the probability that the entire batch will be accepted?

Probability of none defective, so P(X = 0).

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,2100,3,60) = \frac{C_{60,0}*C_{2040,3}}{C_{2100,3}} = 0.9167

0.9167 = 91.67% probability that the entire batch will be accepted

5 0
2 years ago
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