3 years ago

Given f(x) = x^3-3 , find f(-2). Show work please

Mathematics

1 answer:

Tasya [4]3 years ago

8 0

(-2)×3-3=-9
f(x) = -9

You might be interested in

apex if you put down 15% on a $9000 car and pay monthly payments of $189.40 for 48 months what is the total price of the car

defon

The total amount payable for the car if you put a down 15% on a $9000 car and payment of $189.40 for 48 months will be:

Amount=(15/100×9000)+(189.40×48)

=1350+9091.2

=10,441.2

The total amount of money paid for the car after a period of time will be $10,441.2

6 0

3 years ago

Does x+y=1 have an x-intercept of (1,0) and y intercept of (0,1)?

aivan3 [116]

Answer:

Yes

Step-by-step explanation:

To find the y intercept of this formula, you first need to convert it into slope intercept form.

x+y=1

y=-x+1

Here, the slope is negative 1 and the y intercept is (0,1). If you imagine the line with a slope of negative 1, it will indeed cross the x axis at (1,0). Hope this helps!

4 0

3 years ago

For the function f(x) = 3x ^ 2 - 8 what is the average rate of change on the interval from to 10?

denis-greek [22]

Answer:

Step-by-step explanation:

Start from left to right

7 0

3 years ago

Read 2 more answers

If your have 4096 cube

vekshin1

Answer:

a) $\sqrt[3]{4096} = 16$

b) 4096/ 4 = 1024

Step-by-step explanation:

3 0

3 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

3 years ago