Given f(x) = x^3-3 , find f(-2). Show work please

Mathematics

1 answer:

Tasya [4]3 years ago

8 0

(-2)×3-3=-9
f(x) = -9

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Please help me I really need this

pshichka [43]

Answer:

Step-by-step explanation:

Draw a horizontal line at the end of the 8 meter horizontal line.

Find the area of the horizontal rectangle

L = 8 + 3

W = 2

Area = L*w

Area = 11*2

area = 22 m^2

Now do the vertical rectangle

L = 8

w = 3

Area = L*w

Area = 8 * 3

Area = 24 m^2

Total Area = 24 + 22 = 46 m^2

7 0

2 years ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$