1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ulleksa [173]
3 years ago
8

A company says that the probability of finding an all-star card in a game pack is 12.5%. A student wants to determine the probab

ility that, if he buys 6 game packs, 2 or more will have an all-star card. To do this, he uses a random number table to pick 6 numbers from 1 to 8. He lets 1 represent a pack with an all-star card and 2 through 8 represent a pack without an all-star card. He repeats this for a total of 15 trials. The results are shown in the table. 561673 366468 314255 361362 838443 126285 257231 768551 652585 468113 123711 322764 487626 783134 384664 Select from the drop-down menus to correctly complete each statement. To estimate the probability that 2 or more out of 6 packs will have an all-star card, the student must count the number of trials with and divide by the number of trials. This gives an estimated probability of about . 20 pts for the first one to answer and if it is correct you get brainiest answer
Mathematics
2 answers:
Blababa [14]3 years ago
7 0

Answer:

The estimated probability is about:

0.1333=13.33%

Step-by-step explanation:

It is given that:

The probability of finding an all-star card in a game pack is 12.5%.

A student wants to determine the probability that, if he buys 6 game packs, 2 or more will have an all-star card.

He uses a random number table to pick 6 numbers from 1 to 8.

He lets 1 represent a pack with an all-star card and 2 through 8 represent a pack without an all-star card.

The results of 15 trials are given as:

561673   366468    314255    361362    838443   126285    257231   768551    652585    468113    123711    322764    487626    783134    384664

So, the number of trials that have two or more 1 in it will represent the trial that 2 or more out of 6 packs will have an all-star card.

Number of trials that represent that 2 or more out of 6 packs have an all-star are:2

( Since, the trials are: 468113 and   123711 )

Hence, the estimated  probability that 2 or more out of 6 have an all-star is:

2/15=0.13333=13.33%

sveticcg [70]3 years ago
4 0

Answer:

2 or more 1s and .13

Explanation:

i took quiz :D

You might be interested in
5/6÷5=___<br><br>3/7÷6=___<br><br>5/8÷8=___<br><br>15/8÷5​=___
alexandr1967 [171]

Answer:

1/6

1/14

5/64

3/8

Step-by-step explanation:

Easiest and fastest way to evaluate these is to plug it into a calc.

7 0
3 years ago
A Monarch Butterfly can fly 50 miles per day. How long would it take him to fly 2,500 miles?​
lisov135 [29]

Answer:

50 days

Step-by-step explanation:

2500/50 = 50

Answer: 50 days

3 0
2 years ago
Please help me volume is 9881.25 but yeah please help mee
erik [133]

Answer:

20.4

Step-by-step explanation:

see image

5 0
1 year ago
A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i
zzz [600]

Answer:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

\hat p=\frac{36}{100}=0.36 estimated proportion of people who take R supplement

p_o=0.39 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:  

Null hypothesis:p=0.39  

Alternative hypothesis:p \neq 0.39  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615  

The p value for this case would be:

p_v =2*P(z  

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

8 0
2 years ago
LIAM GRAPHS HOW FAR HE BIKES EACH DAY. WHAT IS THE CONSTANT OF PROPORTIONALITY BETWEEN THE MILES HE BIKES AND THE DAY
Dvinal [7]
I will have to see it in numbers
3 0
3 years ago
Other questions:
  • ! The snowfall between midnight and 6 A.M.
    11·1 answer
  • Expand.<br>Your answer should be a polynomial in standard form.<br>(2x- 4) (2x- 6) =​
    15·2 answers
  • What is 63×.04 as a decimal
    8·1 answer
  • 25 POINTS to answer question!
    15·2 answers
  • You throw a dart at the board shown. Your dart is equally likely to hit any point inside the square board. Find the probability
    10·1 answer
  • What is the formula for combinations
    6·1 answer
  • Suppose you have two skateboard ramps. What information do you need to know to prove that the triangular ramps are congruent usi
    15·1 answer
  • 100 points people please help asap!
    7·1 answer
  • Convert the given radian measure to a degree measure. 1.1π
    7·1 answer
  • The ratio of two side lengths for the triangle is given. What is the value of “q” AB:BC is 3:4
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!