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3 years ago

Solve 5(2 - x) = 7x - 26 Input ONLY the value of x.

Mathematics

1 answer:

Alexxx [7]3 years ago

8 0

Answer:

x = 3

Step-by-step explanation:

5(2 - x) = 7x - 26

Distribute;

10 - 5x = 7x - 26

Add 5x to both sides;

10 = 12x - 26

Add 26 to both sides;

36 = 12x

Divide both sides by 12;

x = 3

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Serjik [45]

Answer:

-5/24

Step-by-step explanation:

-3/8 =

-9/24

1/6 =

4/24

-9/24+4/24=-5/24

5 0

3 years ago

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If cos⁡ x=−45, and 180° < x < 270°, what is tan⁡(2x)?

iVinArrow [24]

$Tan2x =\frac{-24}{7}$

<u>Step-by-step explanation:</u>

Here we have , cos x = -4/5 ( corrected as given -45 which is not possible ) ,

180° < x < 270° i.e. in third quadrant . We need to find tan⁡(2x) . Let's find out:

⇒ $Tan\alpha = \frac{sin\alpha }{cos\alpha }$

⇒ $Tan\alpha = \frac{\sqrt{1-(cos\alpha)^2} }{cos\alpha }$

⇒ $Tan\alpha = \frac{\sqrt{1-(\frac{-4}{5})^2} }{\frac{-4}{5} }$

⇒ $Tan\alpha = \frac{-5}{4}\sqrt{1-(\frac{16}{25}) }$

⇒ $Tan\alpha = \frac{-5}{4}\sqrt{(\frac{25-16}{25}) }$

⇒ $Tan\alpha = \frac{-5}{4}(\frac{3}{5}) }$

⇒ $Tan\alpha = \frac{-3}{4}$ , since in third quadrant . $Tan\alpha = \frac{-3}{4}$ remains same .

Now , $Tan2x = \frac{2tanx}{1-(tanx)^{2}}}$

⇒ $Tan2x = \frac{2tanx}{1-(tanx)^{2}}}$

⇒ $Tan2x = \frac{2(\frac{-3}{4})}{1-(\frac{-3}{4})^{2}}}$

⇒ $Tan2x = \frac{-3}{2}(\frac{16}{7})$

⇒ $Tan2x =\frac{-24}{7}$

Therefore, $Tan2x =\frac{-24}{7}$ .

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4 years ago

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Evgesh-ka [11]

2b 2a
----------------- + -----------------
(b+a)^2 (b^2 - a^2)

2b 2a
= ----------------- + -------------------
(b+a)(b+a) (b+a)(b-a)

2b(b - a) + 2a(b + a)
= ------------------------------------
   (b+a)(b+a)(b-a)

2b^2 - 2ab + 2ab + 2a^2
= ---------------------------------------
     (b+a)(b+a)(b-a)

2b^2 + 2a^2
= ------------------------
   (b+a)(b+a)(b-a)

2(b^2 + a^2)
= ------------------------
   (b+a)^2 (b-a)

Answer:

Numerator: 2(b^2 + a^2)
Denominator: (b+a)^2 (b-a)

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Step-by-step explanation:

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Dafna1 [17]

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Step-by-step explanation:

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