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PilotLPTM [1.2K]

3 years ago

9

Please help!!!!! It's urgent

1 answer:

Evgesh-ka [11]3 years ago

7 0

2b 2a
----------------- + -----------------
(b+a)^2 (b^2 - a^2)

2b 2a
= ----------------- + -------------------
(b+a)(b+a) (b+a)(b-a)

2b(b - a) + 2a(b + a)
= ------------------------------------
   (b+a)(b+a)(b-a)

2b^2 - 2ab + 2ab + 2a^2
= ---------------------------------------
     (b+a)(b+a)(b-a)

2b^2 + 2a^2
= ------------------------
   (b+a)(b+a)(b-a)

2(b^2 + a^2)
= ------------------------
   (b+a)^2 (b-a)

Answer:

Numerator: 2(b^2 + a^2)
Denominator: (b+a)^2 (b-a)

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Answer:

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Marrrta [24]

Answer:

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Step-by-step explanation:

By the triangular law of vector addition:

$\vec {CY}=\vec {CA}+ \vec{AY}$

$\vec {CY}=a - 2b$

We have that;

$\frac{YB}{AY} = \frac{3}{1}$

$\implies YB = 3 AY \\ \vec {YB} = 3 \vec {AY}$

$\vec {YB} = 3 a$

From triangle ABC,

$\vec{BC}=\vec{BA}+\vec{AC} \\ \vec{BC}=2b - 4a$

Again from triangle XYB

$\vec{XY}=\vec{YB}+\vec{BX} \\$

$\vec{XY}=\vec{YB}+ \frac{1}{2} \vec{BC}$

$\vec{XY}=3a+ \frac{1}{2} (2b - 4a)$

$\vec{XY}=3a+ b - 2a \\ \vec{XY}=a+ b$

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Tanya [424]

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Which expression is equivalent to<br> %?

olganol [36]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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