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3 years ago

Find a number that has 4 identical even factors each factor must be greater than one and can have only one and itself as factors

Mathematics

2 answers:

wel3 years ago

6 0

Answer:

The Number is 16.

Step-by-step explanation:

Given: Number has 4 Factors.

All 4 factors are same and even.

Factor are greater than 12.

Factors can only has 2 factors that is 1 and itself or we can say factors are prime no.

We need to find this number.

We know that there is only 1 number which is even prime.

So, our required factor is 2.

And required Number = 2 × 2 × 2 × 2 = 16

Therefore, The Number is 16.

r-ruslan [8.4K]3 years ago

3 0

A number that has only 1 and itself as factors is called a prime number. The only even number (a number divisible by 2) that is also a prime number is 2. So a number that has 2 as its factor 4 times is 8 :)

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