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3 years ago

A standard working day is 8 hours. If you were to work 125% of a normal day, how many total hours would you work?

Mathematics

2 answers:

Soloha48 [4]3 years ago

8 0

Whenever we see "of" we know its multiplication

125% x a normal day

125% x 8

$\frac{125}{100}$ x 8

Naya [18.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

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In the diagram, R, S, and T are all points of tangency. What is the perimeter of Triangle<br> XYZ?

Molodets [167]

Answer:

54 cm

Step-by-step explanation:

Perimeter = TZ + TX + RX + RY + SY + SZ

TZ = 5 cm

TX = 13 cm

RY = 9 cm

RX = TX = 13 cm (tangents drawn from and external point)

SY = RY = 9 cm (tangents drawn from and external point)

SZ = TZ = 5 cm (tangents drawn from and external point)

Plug in the values:

Perimeter = 5 + 13 + 13 + 9 + 9 + 5 = 54 cm

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2 years ago

What are the opposites of these numbers

MakcuM [25]

Would it be
1) -4.25
2) -5 1/4
3) -1/2
4) -2 1/3
5) 3.85
6) 6.1

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3 years ago

A ride-all-day amusement park ticket last season was $35, and this season it is $27

Sergio [31]

Answer:

Step-by-step explanation:

35-27=8

4 0

10 months ago

Read 2 more answers

Um ok i need help pls give correct answers

vesna_86 [32]

-a) function 2, function 4
-b) function 4
-c) function 2

4 0

2 years ago

Read 2 more answers

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

3 years ago