What words math with 24

What is the value of x? 10 2x

Viktor [21]

Answer:

The only way of getting to 10 using 2x it should mean that x = 5

2 * 5 = 10

4 0

3 years ago

2a + 4 > 12 qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

nika2105 [10]

Answer:a>4

Step-by-step explanation:

7 0

2 years ago

At a bakery, Victor makes 20 cupcakes. He puts themin equal rows with 10 cupcakes in each row. Whichcalculation can be used to f

Anna [14]

Calculation = 20/10

Number of cupcakes Victor makes = 20

He puts them in equal rows:

Each row contains = 10 cupcakes

To know the number of rows he placed the 20 cupcakes,

we would divide 20 by 10

$\begin{gathered} \text{Number of rows = }\frac{20}{10} \\ \text{number of rows = 2} \end{gathered}$

Calculation = 20/10

The number of rows of cupcakes Victor makes = 2

4 0

1 year ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

Which statements are true about the interquartile range? Select all that apply.

PilotLPTM [1.2K]

Answer:

The true statements are:

B. Interquartile ranges are not significantly impacted by outliers

C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

Step-by-step explanation:

The interquartile range is the difference between the first and third quartiles

Steps to find the interquartile range:

Put the numbers in order
Find the median Place parentheses around the numbers before and after the median
Find Q1 and Q3 which are the medians of the data before and after the median of all data
Subtract Q1 from Q3 to find the interquartile range

The interquartile range is not sensitive to outliers

Now let us find the true statements

A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (because the interquartial range is the difference between the lower and upper quartiles)

B. Interquartile ranges are not significantly impacted by outliers ⇒ True (because it does not depends on the smallest and largest data)

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True (because IQR = Q3 - Q2)

D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (because a small interquartile means data is not spread far away from the median)

E. The data values should be listed in order before trying to find the interquartile range ⇒ True (because we can find the interquartial range by finding the values of the upper and lower quartiles)

4 0

3 years ago

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What words math with 24 - (6+3)