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topjm [15]
3 years ago
5

4(x+9)=8x-7 Solve for x

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

x = 10.75

Step-by-step explanation:

4(x+9)=8x-7

Step 1: Distribute the 4 to the x and 9

4 * x = 4x

4 * 9 = 36

We now have 4x + 36 = 8x - 7

Step 2: add 7 to both sides

36 + 7 = 43

-7 + 7 cancels out

We now have 4x + 43 = 8x

Step 3 subtract 4x from both sides

4x - 4x cancels out

8x - 4x = 4x

We now have 4x = 43

step 4 divide both sides by 4

4x / 4 ( the 4s cancel out and we're left with x )

43/4 = 10.75

We're left with x = 10.75

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Sam gets paid a set rate in his allowance for making his bed every morning. His rate is $0.50 earned for every morning that he m
AlekseyPX

Answer:

bottom graph of left picture

Step-by-step explanation:

For each day he makes his bed, he earns $0.50

In 1 day he earns $0.50

In 2 days he earns $1.00

In 3 days, he earns $1.50

...

In 8 days, he earns $4.00

Look in the 4 graphs.

Which graph has the following points, (1, 0.5), (2, 1), 3, 1.5), ... , (8, 4)?

It is the second graph (bottom graph of left picture.)

4 0
2 years ago
How do i solve this?
vazorg [7]
Usually I would use my head, but you can use whatever you want.
3 0
2 years ago
The probability of getting a head when a biased coin is tossed is . The coin is tossed three times. Find the following probabili
S_A_V [24]

Answer:

a) P(three tails) = \frac{1}{8}

b) P(two tails followed by one head) = \frac{1}{8}

Step-by-step explanation:

coin is tossed three times so, outcome is

HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.

Hence sample space will be

S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}

chance of getting three tails is '1' i.e. TTT

hence,

P(three tails) = \frac{1}{8}

two tails followed by one head is TTH

so, chance of getting that outcome is also '1'

hence,

P(two tails followed by one head) = \frac{1}{8}

6 0
3 years ago
How do I solve this absolute value in quality problem <br><br> |2t + 2/3|≤4
xenn [34]

Answer: -7/3≤t≤5/3

Step-by-step explanation:

|2t + 2/3|≤4

2t + 2/3≤4

(2t + 2/3≤4)*3

6t+2≤12

6t≤10

t≤10/6

<u>t≤5/3</u>

2t + 2/3>=-4

(2t + 2/3>=-4)*3

6t + 2>=-12

6t>=-14

t>=-14/6

<u>t>=-7/3</u>

-7/3≤t≤5/3

6 0
2 years ago
1. Slove the system of equations, first by graphing, and then algebraically. (8 points) y=x-2 and y=-2x+7
Anton [14]

The solution of the equation is x=3 and y=1

Explanation:

The equations are y=x-2 and y=-2 x+7

First we shall solve the equation graphically.

The image of the graph is attached below.

This contains the solution to the system of equations.

The equations y=x-2 and y=-2 x+7 are plotted on the graph.

The intersection of these two equations are the solutions of the system of equations.

Thus, the intersection of the two equations are x=3 and y=1

Now, we shall solve the equation algebraically.

Let us solve the equation using substitution method.

Let us substitute y=x-2 in y=-2 x+7, we get,

x-2=-2x+7

Adding both sides by 2x, we have,

3x-2=7

Adding both sides by 2, we get,

3x=9

Dividing both sides by 3,

x=3

Thus, the value of x is 3.

Substituting x=3 in y=x-2, we get,

y=3-2\\y=1

Thus, the value of y is 1.

Hence, The solution of the equation is x=3 and y=1

4 0
3 years ago
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