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nikklg [1K]
3 years ago
6

Rational equations representing work and rate

Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

3.6hours

Step-by-step explanation:

kevin-6hrs

so he gets 1/6 called in 1 minute

Anne-9 hrs

so she gets 1/9 called in 1 minute

together

1/6+1/9=5/18 called in one minute

so what about all which are 18/18

you get 3.6 hrs I guess

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The line through the midpoint of and perpendicular to the segment joining points (1, 0) and (5, -2). The answe is x_ _= somethin
guapka [62]
First, you have to find the midpoint of the segment. Using the midpoint theorem, (which is (x1+x2)/2, (y1+y2)/2 ) the midpoint of that segment in (3,-1)

Next find the slope of the segment 1,0 and 5,-2  using rise over run or deltax / deltay which is a fancy way of saying change in x over change in y. 

The slope is 4/2 or 2 
When a line is perpendicular to another the slope is the negative reciprocal so the slope of our new line will be -1/2

Now plug in the coordinate (3, -1)  to find the y-intercept and the equation of that line will be complete


so -1 = -1/2 (3) +b
-1= -1.5 +b
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The final equation will be -1/2x + 0.5 =y

hope this helps:)

4 0
4 years ago
I need help with this question please
ikadub [295]

Answer:

Just connect points Y and D with a straight line to make YD. Do the same for YE and YF, just attach Y to points E and F with a straight line.

5 0
3 years ago
Roget Factory has budgeted factory overhead for the year at $4,640,000. It plans to produce 2,000,000 units of product. Budgeted
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Answer:

$15.4

Step-by-step explanation:

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3 years ago
How does finding a cure route differ from finding a square root of a positive integer? How do you the answers differ?
Studentka2010 [4]

Answer:

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Step-by-step explanation:

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3 years ago
Find a common solution for each system of equations:<br> y=3x+5<br> y=-5x-3
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\left\{\begin{array}{ccc}y=3x+5\\y=-5x-3\end{array}\right\\\\substitution\ method\\\\3x+5=-5x-3\\3x+5x=-3-5\\8x=-8\ \ \ \ \ /:8\\x=-1\\\\y=3(-1)+5=-3+5=2\\\\Solution:x=-1\ and\ y=2.

graphing\ method\\\\  \left\{\begin{array}{ccc}y=3x+5\\y=-5x-3\end{array}\right\\------------------\\y=3x+5\\y-intercept\ (x=0)\\y=3(0)+5=5\\(0;\ 5)\\x-intercept\ (y=0)\\3x+5=0\\3x=-5\\x=-\frac{5}{3}\\(-\frac{5}{3};\ 0)\\---------------------
y=-5x-3\\y-intercept\ (x=0)\\y=-5(0)-3=-3\\(0;-3)\\x-intercept\ (y=0)\\-5x-3=0\\-5x=3\\x=-\frac{3}{5}\\(-\frac{3}{5};\ 0)\\\\Solution:((-1;\ 2)\to x=-1\ and\ y=2.

8 0
4 years ago
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