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OleMash [197]
3 years ago
14

You are getting a line-up ready for a school kickball game. You have 7 girls and 7 boys. The rules state each child must kick th

e same number of times and alternate girl-boy or boy-girl. How many ways can a line-up be made for one round of kicking?
Mathematics
1 answer:
Effectus [21]3 years ago
8 0

Answer:

50,803,200 ways

Step-by-step explanation:

In this situation, since you should alternate girl-boy or boy-girl, the line-up can either start with a boy or a girl kicking which would yield one of the two following patterns:

BGBGBGBGBGBGBG or GBGBGBGBGBGBGB.

For each of those patterns, there are 7! ways to arrange all boys and 7! ways to arrange all girls. The number of ways that a line-up can be made for one round of kicking is:

n=2*7!*7!\\n=2*(7*6*5*4*3*2)^2\\n=50,803,200\ ways

There are 50,803,200 ways to set the line-up.

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Please Help Me On This
anastassius [24]

Answer:

X2 = (-2, 1), W2 = (-4, 1), Y2 = (4, -2), Z2 = (-3, 2)

Step-by-step explanation:

First, flip across the y-axis:

Coordinates: X1 = (2, -1), W1 = (4, -1), Y1 = (2, -4), and Z1 = (3, -2)

Then, rotate 180 degrees counterclockwise:

Coordinates: See above

5 0
3 years ago
Is 21/48 greater or less than 1/2
Svetlanka [38]
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No.

Half of 48 would be 24, not 21

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6 0
3 years ago
What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

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2 years ago
If f(x)=x^2+4x and g(x)=2x+2 find f(5)+g(6)
Veseljchak [2.6K]
F(5)= 5^2+4(5) = 25+20=45
g(6)= 2(6)+2 = 14
f(5)+g(6) = 45+14 = 59
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3 years ago
The quadratic function g(x)=ax^2+bx+c has the complex roots (-5+9i) and (-5-9i).
Gekata [30.6K]

Answer:

I don't know sorry

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2 years ago
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