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2 years ago

Find the radius of a circle if it’s circumference is numerically equal to its area

Mathematics

1 answer:

kotykmax [81]2 years ago

5 0

Answer:

Step-by-step explanation:

hello :

if : r the radius ( r ≠0)

the circumference is : 2πr

the area is : πr²

so : πr² = 2πr

simplify by : r π you have : r=2

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T= m/x + p for m. Find m

Usimov [2.4K]

You only have variables, so this problem is unsolvable

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3 years ago

Find the solutions of the quadratic equation - 2^2+ 3x – 3 = 0

Assoli18 [71]

Answer:

-1/3

Step-by-step explanation:

2^2 + 3x - 3 = 0

4 - 3 + 3x = 0

1 + 3x = 0

x = -1/3

Hope it helps

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2 years ago

James walked 548 yards. How many miles has he walked ? A. 337/440 miles B. 33/44 miles C. 1/4 miles D. 337/460 miles

blondinia [14]

548yds(3ft/yd)(mi/5280ft)=137/440 miles

You have a typo in your answers or maybe there is an E. none of the above :)

6 0

3 years ago

Read 2 more answers

What is the answer for <br>5/8 _ 1/4

ZanzabumX [31]

Answer:

4or 4/1

Step-by-step explanation:

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2 years ago

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

7 0

3 years ago

Read 2 more answers