This question is hard for me to answer can you help me. The question is find the value of x.
1 answer:
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Answer:
Coordinates of vertices of rectangle A B CD are A(1,11), B(3,1).
Equation of line AB is
⇒y-1=-5(x-3)
⇒y-1= -5 x+15
⇒y+ 5 x=1+15
⇒y+5 x=16→[ Equation of line that contains line segment AB]
Equation of line perpendicular to AB is
x- 5 y +k=0
Since it passes through A(1,11).
1-5×11+k=0
1-55+k=0
k-54=0
k=54
So equation of AB is
x-5 y+ 54=0
So equation of line, containing line segment AD is
→x-5 y+54=0
Answer:
The slope of the line is -2
Step-by-step explanation:
<em>The rule of the slope of a line is</em>:
, where
and
are two points on the line
<em>Let us find the slope using the rule above</em>
∵ The line passes through points (3, -7) and (-1 , 1)
∴ = 3 and
= -1
∴ = -7 and
= 1
<em>Substitute these values in the rule above to find m</em>
∴
∴ The slope of the line that passes through the given points is -2
Step-by-step explanation:
1st) Distribute 8 with x and 8 with -1 which will give you
8x-8=5x-35
2nd) Use opposite operation and add 8 both sides
8x-8=5x-35
+8 +8
---------------
8x=5x-27
3rd) subtract 5x from both sides
8x=5x-27
-5x= -5x
_______
3x=-27
4th) Divide 3 from both sides so -27 by 3
3x=-27
_ _
3 3
ANSWER X=-9
