Answer:
B. There is one real, double root
Step-by-step explanation:
For ax² + bx + c = 0, the discriminant is b² − 4ac.
If the discriminant is positive and a perfect square, there are two real, rational roots.
If the discriminant is positive and not a perfect square, there are two real, irrational roots.
If the discriminant is 0, there is one real, double root.
If the discriminant is negative, there are two complex roots.
Here, a = 64, b = -16, and c = 1.
b² − 4ac
= (-16)² − 4(64)(1)
= 0
The discriminant is 0. Therefore, there is one real, double root
