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Nezavi [6.7K]
2 years ago
10

If f(x) = -2x + 4, then f^-1(x) =

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
7 0

Answer:

f^{-1}(x) = -\frac{x}{2} +2

Step-by-step explanation:

Consider the real number y such that  f ⁻¹(x) = y

f^{-1}\left( x\right)  =y\Longleftrightarrow f\left( y\right)  =x

We need to find y in order to determine the expression of  f ⁻¹(x)

f(y) = x ⇔ -2y + 4 = x

⇔ 4 - x = 2y

⇔ y = (4 - x)/2

\Longleftrightarrow y=-\frac{x}{2} +2

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-250 feet most likely is the answer

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3 years ago
(2.5×10−8)(9×10−10)<br><br> Express your answer in scientific notation.
Lunna [17]
Answer: 2.25x 10^{-17}

Scientific notation is used in science because the number can be vary from so much that using decimal is making it hard. The number expressed in 10^{x} form. Both number in the question is already in scientific notation. Then to multiply the number and keep it at scienfitic notation the calculation should be:

2.5 x 10^{-8}x 9 x 10^{-10}= 22.5 x 10^{-18}= 2.25x 10^{-17}

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Read 2 more answers
Evaluate (98 x 102) by using suitable identities.
GREYUIT [131]

Answer:

The answer is 9996

Step-by-step explanation:

Using the identity (x+a)(x+b) = x  ^2  +(a+b)x+ab

Writing 102 as 100+2 and 98 as 100−2

Hence (100+2)(100−2) = 100  ^2  +[2+(−2)]100+(2)(−2)

= 10000+(0)100−4

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The answer is 9996

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3 years ago
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The slope of the tangent line to the curve x^3y+y^2-x^2=5 at the point (2,1) is
zheka24 [161]

Answer:

-4/5

Step-by-step explanation:

To find the slope of the tangent to the equation at any point we must differentiate the equation.

x^3y+y^2-x^2=5

3x^2y+x^3y'+2yy'-2x=0

Gather terms with y' on one side and terms without on opposing side.

x^3y'+2yy'=2x-3x^2y

Factor left side

y'(x^3+2y)=2x-3x^2y

Divide both sides by (x^3+2y)

y'=(2x-3x^2y)/(x^3+2y)

y' is the slope any tangent to the given equation at point (x,y).

Plug in (2,1):

y'=(2(2)-3(2)^2(1))/((2)^3+2(1))

Simplify:

y'=(4-12)/(8+2)

y'=-8/10

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Dmitry_Shevchenko [17]

Answer:

1.049

Step-by-step explanation:

Divide 103 into 108

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