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AleksAgata [21]
3 years ago
8

An environmental (soil) sample obtained from a temperate region was transferred to a liquid growth medium and incubated at 30°C

for 24 hours, then transferred to solid growth medium in order to isolate bacteria from the original sample. Following 48 hour incubation at 30°C, the picture of the solid medium shows the results of this experiment. Which of the following statement(s) among A D are true regarding this experiment? A.This plate represents a pure cultu B Isolates A and B are likely the only bacterial types that would have been present in the original environmental sample. A and B are probably the same microorganism D.I dentification of microbial types in the environmental sample could have been attempted without culturing anything. two of of A D are correct F three of A - D are correct

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Missing Question:

The question was missing information. I have found the question online and attaching it here for convenience.

Answer:

Option D

Explanation:

  • From the picture, we can see two types of bacteria (i.e. A and B), therefore it is not a pure culture.
  • We can not predict whether any culture has been lost during incubation.
  • A and B are different organisms.

Hence, the only correct option is D, which states:

"Identification of microbial types in the environmental sample could have been attempted without culturing anything."

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There is a group tour at the museum every 20 minutes. A movie about the exhibit begin every 45 minutes. Both begin at 9am. What
AlladinOne [14]
This question is best answered by finding the least common multiple of both 45 and 20.  If a scenario indicates every so many, it would be like listing the multiples.  It can be harder to list the multiples of bigger numbers (45, 90, 135, 180 and 20, 40, 60, 80, 100, 120, 140, 160, 180), so another strategy is to use prime factorizations.  The prime factorization of 45 is <em>3</em> x <em>3</em> x 5 and the prime factorization of 20 is <em>2</em> x <em>2</em> x 5. The numbers that are the same in both prime factorizations are part of your answer.  All other numbers (the italicized ones) also become a factor in your final answer, so 5 x 3 x 3 x 2 x 2 = 180.  This means 180 minutes later they both start again at the same time.  So 3 hours from 9 am is 12 noon.
6 0
4 years ago
Holly missed 7 of 181 school days this year. Approximately what percent of school days was Holly in attendance?
kogti [31]

Answer:

96.13%

Step-by-step explanation:

181-7=174. 174/181

5 0
3 years ago
-7/8*(- 3/8)= whts the answer ?
Kamila [148]

\text {Hi! Let's Solve this Problem!}

\text {We know that Multiplying a Negative to a Negative will Equal a Positive.}

\text {\underline {Multiply}}

\text {-7/8*(-3/8)=}

\text {Your Answer Would Be:}

\fbox {21/64}

\text {Best of Luck!}

4 0
3 years ago
1. Suppose D has a coordinate of 11 and DE = 5. What are the possible<br> midpoints of DE?
Rasek [7]

Answer:

The possible midpoints are (5.5,8) and (5.5,3)

Step-by-step explanation:

Given

D = 11

DE = 5

Required

Determine the midpoint of DE

First, we need to determine the coordinates of E

If E is to the right of DE;

E - D = 5

E - 11 = 5

E = 11 + 5

E = 16

Hence, the coordinate is (11,16)

Midpoint = \frac{1}{2} * (11,16)

Midpoint =  (5.5,8)

Else:

D - E = 5

11 - E = 5

E = 11 - 5

E = 6

Hence, the coordinate is (11,6)

Midpoint = \frac{1}{2} * (11,6)

Midpoint = (5.5,3)

<em>The possible midpoints are (5.5,8) and (5.5,3)</em>

6 0
3 years ago
Pleas help :)))))))))
Oksi-84 [34.3K]

The highest age range in attendance was 15-45 and the number of attendees ages 5-15 was 20.

6 0
3 years ago
Read 2 more answers
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