Fine the domain and the range is the given relation.{(-6,3), (3,-9), (-4,1), (1,-4)}
1 answer:
Answer:
Domain: [-6, 3, -4, 1]
Range: [3, -9, 1, -4]
Explanation:
if a particular relation is written as
the x is the input value and y is the output value.
The domain is defined as all possible input values a relation can take.
The range is defined as all possible output values a relation can take.
Now in our case, the relation we have is {(-6,3), (3,-9), (-4,1), (1,-4)}. Therefore, the all possible domain values we have are [-6, 3, -4, 1].
All output values that our relation can take are 3, -9, 1, and -4. Therefore, the range is [3, -9, 1, -4].
Hence, to summerise,
Domain: [-6, 3, -4, 1]
Range: [3, -9, 1, -4]
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we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
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distribute
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add x^2 to both sides
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subtract 8x
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if you have
ax^2+bx+c=0 then x=
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=
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x=
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28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=
x=
x=
x=
x=
there are no real numbers that satisfy this