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3 years ago

How do you write 4x+y=15 in function form?

Mathematics

1 answer:

sleet_krkn [62]3 years ago

3 0

Answer:

if you mean y-mx+b form

Step-by-step explanation:

y =− 4 x+15

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Which 2 organic compounds serve as energy sources? How do these 2 groups differ?

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Try glucose (C6H1206) and water (H2O)?

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3 years ago

A bowl of fruit is on the table. It contains 5 apples, 2 oranges, and 2 bananas. Christian and Aaron come home from school and r

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The probability that both grab oranges would be = $\frac{1}{36}$

Step-by-step explanation:

Given,

A bowl contains,

Apples = a = 5

Oranges = o = 2

bananas = b = 2

Total fruits in bowl = x = a + o + b = 5 + 2 + 2 = 9

Now, Christian and Aaron come home from school and randomly grab one fruit each.

The probability of first selecting orange would be = $\frac{o}{b} = \frac{2}{9}$

Now, the oranges left would be 2 - 1 = 1

and total fruits would be = 9 - 1 = 8

Hence, the probability of selecting second orange would be = $\frac{1}{8}$

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3 years ago

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I believe the second one : drawing a number from a hat, not replacing it, and then drawing a second number

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Can someone help me out?

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Answer: It would be C

Step-by-step explanation:

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Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

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Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

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4 years ago