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3 years ago

2-2(x-25) what is the answer?

Mathematics

2 answers:

BartSMP [9]3 years ago

5 0

Answer:

F= 2

F=-2

F=x-25

Step-by-step explanation:

DerKrebs [107]3 years ago

4 0

-271 thank me later dude

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Write it as a product: -<img src="https://tex.z-dn.net/?f=ax%5E%7B6%7D" id="TexFormula1" title="ax^{6}" alt="ax^{6}" align="absm

IrinaK [193]

Answer:

$\frac{-abx^{6}+1 }{b}$

Step-by-step explanation:

4 0

3 years ago

In 1990, Dawn gross pay was $48,000.

forsale [732]

A. Dawn's gross monthly pay is $4,000 ($48,000/12).

B. The month that Dawn hit her maximum taxable Social Security Income is May (5 months from January to May).

C. In February, 1978, Dawn paid $260 in Social Security Tax.

D. In May, 1978, Dawn paid $110.50 in Social Security Tax, which represented the balance.

E. In November, 1978, Dawn paid $0 in Social Security Tax because by May she had completely paid the maximum Social Security Tax of $1,150.50.

<h3>Data and Calculations:</h3>

Gross earnings in 1990 = $48,000

Maximum taxable income in 1990 = $17,700

Social Security Tax Rate = 6.5%

Gross monthly pay = $4,000 ($48,000/12)

Monthly Social Security Tax = $260 ($4,000 x 6.5%)

Total Social Security Tax = $1,150.50 ($17,700 x 6.5%)

In 5 months, Dawn would have paid a total of $1,150.50 ($260 x 4 + $110.50) in Social Security Tax.

Thus, the total Social Security Tax paid by Dawn in that year was $1,150.50.

Learn more about Social Security Tax here: brainly.com/question/9741758

4 0

2 years ago

I NEED HELP ASAP DUE IN 3 MINUTES WHOEVER ANSWERS IT RIGHT GETS BRIANIST

Damm [24]

Answer:

It is D.

Step-by-step explanation:

8 0

3 years ago

if you wanted to know how fast a tiger can run which measurement would you use? A) candela, mole B) kilogram, ampere C) meter, k

Kitty [74]

Meter second would be the correct answer

4 0

4 years ago

Read 2 more answers

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

3 years ago