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liq [111]
2 years ago
6

-50 Points- If segment AC and segment BC are tangent to circle O, find the value of x.

Mathematics
2 answers:
Shkiper50 [21]2 years ago
4 0

Answer:

x = 170 deg

Step-by-step explanation:

A tangent to a circle is perpendicular to the radius of the circle at the point of tangency. That means that in quadrilateral AOBC, angles A and B are right angles and measure 90 deg.

The sum of the measures of the angles of an n-sided polygon is

(n - 2)180 deg

In this case, n = 4, so

(4 - 2)180 deg = 360 deg

m<A + m<O + m<B + m<C = 360

90 + x + 90 + 10 = 360

x + 190 = 360

x = 170

Answer: 170 deg

erik [133]2 years ago
3 0

AOB ( x)  + ACB = 180

AOB (x) + 10 = 180

x = 180-10

x = 170

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Answer:

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Step-by-step explanation:

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Step1: First we need to factorize the denominator of each function.

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Step 2: We will find the LCM of the resulting expression

=  \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\

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Step-by-step explanation:

here is your answer

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