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nikitadnepr [17]
3 years ago
10

To use a compass to find the midpoint of a line segment, Rebecca draws two arcs of equal radius from each of the two endpoints o

f the segment so that they also intersect on both sides of the segment. Identify the line that connects the two points where the arcs intersect.
a. radius of the arcs

b. diameter of the arcs

c. perpendicular bisector of the segment

d. angle bisector
Mathematics
1 answer:
DiKsa [7]3 years ago
3 0
We are given a line segment with two points on each end. Rebecca draws two arcs with equal radius from each point. Now, the intersection of the two arcs is the midpoint of the line. This can be explained by the radius of the arcs. Since they are equal, meaning they have the same distance from each point. Thus, the midpoint of the line. 
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What is the solution to the equation below? Round your answer to two decimal places.
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Answer:

x = 0.5

Step-by-step explanation:

2(2x-1)=3

2(2x)+1=3

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2(2x)=2        2x2=4

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2÷4=0.5

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x = 0.5

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A company's board of directors wants to form a committee of 3 of its members. There are 6 members to choose from. How many diffe
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Order doesn't mater so use combinations:
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Need help doing this
Natali [406]

Answer:

  A.  -2

  B.  -10

Step-by-step explanation:

The slope of a perpendicular line will be the negative reciprocal of the slope of the given line:

  -1/(1/2) = -2 . . . . slope of the perpendicular line

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The y-intercept will let the given point satisfy the equation ...

  y = -2x +b

  2 = -2(-6) +b

  -10 = b . . . . . . . subtract 12. This is the y-intercept.

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The graph shows the two lines and the points they go through.

8 0
3 years ago
4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

7 0
3 years ago
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