Assuming no student was born on Leap Day, and that birthdays are as likely to occur on one day as any other, each student has

probability of being born on a particular day. So if one student's birthday was, say, 1 January, the probability that another student was born on 2 January is

.
The probability, then, of having the next student born on 3 Januaray is

.
Continuing in this fashion, for 25 students you would find that no two share a birthday with probability
Answer:
80%
Step-by-step explanation:
Divide 600 by 750 to find the probability
The roots of the parabola is where the x-intercepts are so the answer is x=-1 and x= 5
Answer: D
Step-by-step explanation:
The range for the thing is greater
Z^3-2z^2-16z+32
Use the grouping method
(z^3-2z^2)(-16z+32)
z^2(z-2)-16z(z-2)
(z^2-16z)(z-2)
Factor more
z(z-16)(z-2) is the final answer