Ask question

Ask question

All categories

2 years ago

13

The box plots show the target heart rates of men 20-40 years old and men 50-70 years old.

1 answer:

Harman [31]2 years ago

6 0

Answer: D

Step-by-step explanation:

The range for the thing is greater

You might be interested in

U=1-3v/vt-w make t the subject

Jobisdone [24]

$u = 1 - \dfrac{3v}{vt-w}$

$\dfrac{3v}{vt-w} = 1 - u$

$3v = (1 - u)(vt - w)$

$3v = vt - w - uvt + wu$

$vt - uvt = 3v + w - wu$

$t(v - uv) = 3v + w - wu$

$t = \dfrac{3v + w - wu}{v - uv}$

8 0

3 years ago

20 Points! Help pls! !

lara31 [8.8K]

Well i think it 120 your welcome

3 0

3 years ago

Read 2 more answers

An x-method chart shows the product a c at the top of x and b at the bottom of x. Above the chart is the expression a x squared

Bond [772]

Answer:

The other factor is (x + 2).

Step-by-step explanation:

If x - 10 is a factor of x^2 - 8x - 20 then we must find another factor that includes +2x, so that we have -10x + 2x = -8x. That factor is (x + 2):

x^2 - 8x - 20 = (x - 10)(x + 2)

As a test, multiply -10 and +2. We get -20, matching the constant of the given polynomial. Also, -10x + 2x = -8x, another match.

9 0

2 years ago

Read 2 more answers

A five-digit number starts with a number between 4-9 in the first position, with no restrictions on the remaining 4 digits. a

Maurinko [17]

Answer:

(a) $Pr = 0.3024$

(b) $Pr = 0.6976$

(c) $Pr = \frac{^9P_{n-1}}{10^{n-1}}$

Step-by-step explanation:

Given

$Start = \{5,6,7,8\}$ i.e. between 4 and 9

$n(Start) =4$

$Digits = 5$

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 10\\$ (i.e. any of the 10 digits 0 - 9)

$Third\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fourth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fifth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

So, the total is:

$Total = 4 * 10 * 10 * 10 * 10$

$Total = 40000$

For selection that all digits are different, the selection is:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 9$ (i.e. any of the remaining 9)

$Third\ digit = 8$ (i.e. any of the remaining 8)

$Fourth\ digit = 7$ (i.e. any of the remaining 7)

$Fifth\ digit = 6$ (i.e. any of the remaining 6)

So:

$Selection =4 * 9 * 8 * 7 * 6$

$Selection =12096$

So, the probability is:

$Pr = \frac{Selection}{Total}$

$Pr = \frac{12096}{40000}$

$Pr = 0.3024$

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

$P(At\ least\ 1) = 1 - P(None)$

So, we have:

$Pr= 1 - 0.3024$

$Pr = 0.6976$

Solving (c): An expression to model the probability.

<em>Using (a) as a point of reference, we have;</em>

$Pr = \frac{Selection}{Total}$

Where

$Selection =4 * 9 * 8 * 7 * 6$ ---- for selection of 5 i.e. n = 5

$Total = 4 * 10 * 10 * 10 * 10$

$Selection =4 * 9 * 8 * 7 * 6$

This can be rewritten as:

$Selection = 4 * ^9P_4$

4 can be expressed as: 5 - 1

So, we have:

$Selection = (5-1) *^9P_{5-1}$

Substitute n for 5

$Selection = (n-1) *^9P_{n-1}$

$Selection = (n-1)^9P_{n-1}$

$Total = 4 * 10 * 10 * 10 * 10$

This can be rewritten as:

$Total = 4 * 10^4$

$Total = (5-1) * 10^{5-1}$

$Total = (n-1) * 10^{n-1}$

$Total = (n-1) 10^{n-1}$

So, the expression is:

$Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}$

$Pr = \frac{^9P_{n-1}}{10^{n-1}}$

<em>Where n represents the digit number</em>

5 0

2 years ago

Write a number in which the value of the 3 is 10 times the value of the digit 3 in 156.32

Marat540 [252]

Answer:

1563.2

Step-by-step explanation:

If you just multiply 0.3 by 10 you will get 3

Now all you need to do is write 3 or have a number which has unit place value of 3

5 0

2 years ago

Read 2 more answers