All categories

3 years ago

If 14 is 7% of the pennies how many are in the pile

Mathematics

2 answers:

irinina [24]3 years ago

5 0

$0.07x=14$

$\frac{0.07x}{0.07}=\frac{14}{0.07}$

$x=200$

dybincka [34]3 years ago

3 0

Let the missing constant be x.

14 = 7% of x.

14 = 7/100 x

7x = 1400

x = 1400/7 = 200
x = 200.

Thus, there are 200 pennies in a pile.

You might be interested in

Alondra received a 14% hourly raise, but the number of hours worked decreased by 7.5%. If her wage was $10.50 an hour and she wo

Elodia [21]

Answer:

She will earn <u>$442.89</u> in one week after the changes.

And this is <u>more</u> than her previous weekly earnings.

Step-by-step explanation:

Given:

Alondra received a 14% hourly raise, but the number of hours worked decreased by 7.5%. If her wage was $10.50 an hour and she worked 40 hours per week before the changes.

Now, to find money she will earn in one week after the changes.

Her wage was = $10.50.

She worked per week = 40 hours.

So, her salary before changes:

$10.50\times 40\\\\=\$420.$

Thus, the salary per week before changes is $420.

Now, to get her salary after 14% hourly raise:

$10.50+14\%\ of\ 10.50\\\\=10.50+\frac{14}{100} \times 10.50\\\\=10.50+1.47\\\\=11.97$

<u>Salary after hourly raise = $11.97 per hour.</u>

Then, to get the number of hours worked decreased by 7.5%:

$40-7.5\%\ of\ 40\\\\=40-\frac{7.5}{100} \times 40\\\\=40-3\\\\=37.$

<u>Number of hours per week after hours of worked decreased = 37 hours.</u>

Now, to get the salary after changes:

<em>Salary after hourly raise × number of hours per week after hours of worked decreased</em>

$=11.97\times 37$

$=\$442.89.$

<u>Salary after changes in one week = $442.89.</u>

<u><em>As, the previous salary was $420 in one week. </em></u>

<u><em>And after changes this salary is $442.89 in one week which is more than previous. </em></u>

Therefore, she will earn $442.89 in one week after the changes.

And this is more than her previous weekly earnings.

4 0

3 years ago

What are the directions when you have an equation?

vladimir2022 [97]

What type of equation? I'm assuming you may mean PEMDAS (Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction), meaning that when solving an equation first you solve anything that's in parenthesis. After that you do exponents and then either multiplication or division, going left to right if there are multiple parts of the equation that require you to do multiplication or division. Then you move on to addition and subtraction, the same rules with multiplication and division apply. Hopefully I explained this well.

8 0

3 years ago

You are graphing Rectangle ABCD in the coordinate plane. The following are three of the vertices of the

egoroff_w [7]

Are you looking for D on the graph? if so, then the final coordinate to complete the rectangle is (-2,-8)

3 0

4 years ago

Which of the following transformations will always produce a congruent figure?

goldenfox [79]

Answer:

the answer to this is A: a reflection

Step-by-step explanation:

4 0

3 years ago

For each sequence, write an explicit and a recursive formula. NO LINKS!!!!

expeople1 [14]

Answer:

a. explicit: an = 16(1/4)^(n-1); recursive: a[1] = 16, a[n] = 1/4·a[n-1]

b. explicit: an = -2 +7(n -1); recursive: a[1] = -2, a[n] = 7+a[n-1]

Step-by-step explanation:

Finding sequence formulas is all about finding and matching patterns. It is generally pretty easy to subtract one term from the next to see if there is a common difference. If the differences are not constant, but terms have the same ratio. then the sequence is geometric.

The forms for explicit and recursive formulas for arithmetic and geometric sequences are shown here. All you need to do is fill in the values of the first term (a1) and common difference (d) or common ratio (r).

<h3>Arithmetic sequence formulas:</h3>

<u>explicit formula</u>:

$a_n=a_1+d(n-1)$

<u>recursive formula</u>:

$a_1 = \text{[first term]};\ a_n=d+a_{n-1}$

<h3>Geometric sequence formulas:</h3>

<u>explicit formula</u>:

$a_n=a_1\cdot r^{n-1}$

<u>recursive formula</u>:

$a_1 = \text{[first term]};\ a_n=r\cdot a_{n-1}$

The first term is 16. There is no common difference, but the common ratio is 4/16 = 1/4.

explicit formula: an = 16(1/4)^(n-1)

recursive formula: a[1] = 16; a[n] = 1/4·a[n-1]

The first term is -2. The common difference is 5-(-2) = 7.

explicit formula: an = -2 +7(n -1)

recursive formula: a[1] = -2; a[n] = 7 +a[n-1]

_____

<em>Additional comment</em>

Term numbers are generally identified by subscripts on the variable. When writing in plain text, subscripts are difficult to create, so we simply write the subscript next to the variable name: an, a1. This is less satisfactory when there is arithmetic in the subscript, as in the recursive formulas. For those, we have written the plain text formulas using square brackets to show the term numbers: a[1], a[n], a[n-1].

The recursive formula for a given term is defined in terms of the previous term in the sequence. In order for that to work, there needs to be a definition of the first term. We have referred to that generically as a1, but the meaning of a1 = a1 in the recursive formula is maybe no so clear. That is why we used a1 = [first term]. The intention is that [first term] be understood to mean the numerical value of the first term of the sequence.

In short, these problems are worked by finding the common ratio or difference, identifying the first term of the sequence, and filling those two values into the generic formulas.

5 0

2 years ago