Pls help !!!!!!!!!!!!!!

Mathematics

1 answer:

garri49 [273]2 years ago

6 0

The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .

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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (39pt

WITCHER [35]

Angle O=64

Side m=7.3159882(rounded if needed)

Side n=16.68902(round if needed)

We are given

Angle M which equal 26.

Angle N equals 90 degrees

Side MN which equal 15.

We are asked to find all the missing elements of the triangle.

Angle O can be found using triangle interior theorem so we can add 90+26+x =180 to find the value that satisfies the x value.

$90 + 26 + x = 180$

$116 + x = 180$

$x = 64$

Angle O=64 degrees

We can find side m by doing law of sines.

$\frac{on}{ \sin(26) } = \frac{mn}{ \sin(64) }$

$\frac{on}{ \sin(26) } = \frac{15}{ \sin(64) }$

$on = \frac{15}{ \sin(64) } \times \sin(26)$

which is 7.315(round if neeeded).

We can find side n using pythagorean theorem,

${15}^{2} + {7.3}^{2} = {n}^{2}$

$225 + 53.29 = {n}^{2}$

$\sqrt{278.29}$

Side n=16.689(round if needed)

4 0

2 years ago

What is the equation of a circle whose radius is 16 units and center is at (2,-5)?

STatiana [176]

Answer:

The general equation of the circle is
$( {x - a})^{2} + ({y - b})^{2} = {r}^{2} \\ therefore \: we \: \: have \: \\ ( {x - 2})^{2} + (y - ( - 5)) {}^{2} = ({16})^{2} \\ ({x - 2})^{2} + ( {y + 5})^{2} = 256$
HOPE THIS HELPS!