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alex41 [277]
3 years ago
12

Pls help !!!!!!!!!!!!!!

Mathematics
1 answer:
garri49 [273]3 years ago
6 0
The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .
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23.5584557678 rounded to the nearest hundredth
hram777 [196]
23.5584557678 = 23.56 <span>rounded to the nearest hundredth

hope it helps</span>
3 0
3 years ago
What are any 9 perfect squares to type in the boxes?
Paul [167]

Answer:

1

4

9

16

25

36

49

64

81

100

Step-by-step explanation:

1 = 1²

4 = 2 x 2 = 2²

9 = 3 x 3 = 3²

16 = 4 x 4 = 4²

25 = 5 x 5 = 5²

36 = 6 x 6 = 6²

49 = 7 x 7 = 7²

64 = 8 x 8 = 8²

81 = 9 x 9 = 9²

100 = 10 x 10 = 10²

4 0
3 years ago
Y= kx+m <br><br> Make x the subject
Ilia_Sergeevich [38]
Kx=y-m
x=(y-m)/k
Note that this is also standard linear form, x=y/k-m/k where slope=1/k and x intercept is -m/k.
7 0
3 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
3 years ago
James trained for the Boston marathon for 3 1/2 hours every day how many hours did he train in the month of June?
n200080 [17]
If you say 3.5 times 30 ur answer would be 105
3 0
3 years ago
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