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Sav [38]
3 years ago
9

What can historians say with confidence that happened during the Battle of Lexington?

Mathematics
2 answers:
Scrat [10]3 years ago
5 0
That the American Revolution started.
RideAnS [48]3 years ago
3 0

Answer: The american revolution was started. Also you posted this under mathematics!

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For 5 through 8, write a statistical question that could be used to gather data on each topic. 5. Distances members of the track
MaRussiya [10]

Step-by-step explanation:

We must ask a question that your answer corresponds to each of the topics in the statement, therefore we will review each one:

5. Distances members of the track team jogged last week

How far did you run last week?

6. Numbers of letters in name of street you live on

How many letters are there in the name of your street?

7. Cost of a restaurant dinner

How much did you pay for dinner?

8. Numbers of cars of different colors in a parking lot

What color is your car?

5 0
3 years ago
Rachna purchases a plant that is 6 inches tall. Every week the plant grows an additional 0.6 inches. Rachna draws a graph of the
aleksklad [387]

Answer:

0.6

Step-by-step explanation:

Slope is the change in y divided by change in x.

x is weeks

y is height

We know plant grows 0.6 inches every week. This means per 1 week [change in x], the plant grows 0.6 inches [change in y]

Slope = 0.6/1 = 0.6

0.6 is the slope of the function

5 0
3 years ago
Ffffffffffffffffffff
scoundrel [369]

Answer:

1

16-7-(2×4)

16-7-(8)

16-7=9-8=1

5 0
2 years ago
30 points!<br>please help<br><br>in return brainliest and special thanks
a_sh-v [17]
21. >

22. Distributive Property
5 0
3 years ago
Read 2 more answers
From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ
bulgar [2K]
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Here we're given
p=0.10  [ success = defective ]
n=3

(a) x=0
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,0)0.1^0(1-0.1)^{3-0}
=1(1)(0.729)
=0.729

(b) x=2
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,2)0.1^2(1-0.1)^{3-2}
=3(0.01)(0.9)
=0.027

(c) x &ge; 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
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