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3 years ago

Pls help me what is 2x+y=-5 rewrite the equation into slope intercept form

Mathematics

1 answer:

Flura [38]3 years ago

5 0

Slope intercept form is y=mx+b. So simply move the 2x to the other side of the equation to get y=-2x-5

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Answer as soon as possible

alexandr1967 [171]

Answer:

C −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

(a+3) ( −2a^2+15a+6b^2)

Distribute the a to the large term in parentheses and the 3 to the large term in parentheses

a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)

−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2

Combine like terms

−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2

-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2

3 0

3 years ago

Read 2 more answers

Help me im dying and i

inessss [21]

Answer:

The better bar to buy is the Nutty Crunch

Step-by-step explanation:

4.74 / 6 = 0.79 per bar

7.80 / 10 = 0.78 per bar

6 0

3 years ago

Read 2 more answers

-2b + 9 = 25<br> ones step and two step equation Screenshot of example

ycow [4]

Answer:

b = -8

Step-by-step explanation:

-2b + 9 =25

-9 = -9

-2b = 16

/-2 /-2

b = -8

3 0

2 years ago

(3) Two people are at an elevator. At the same time one person starts to walk away from the elevator at a rate of 2 ft/sec and t

Gekata [30.6K]

Answer:

The rate at which the distance between the two people is changing 15 seconds later is 7.28 ft/sec.

Step-by-step explanation:

Here, we note the following

Let the person walking way fom the elevator be X

Let the other person going up in the elevator be Y

Therefore after 15 seconds, their positions will be;

For X, 2 ft/sec × 15 s = 30 ft away from the elevator

For Y, 7 ft/sec × 15 s = 105 ft up in the elevator

At that instant, the distance between them is given as

d² = x² + y²

= 30² +105² = 11925 ft²

d = √11925 ft² = 109.202 ft

The rate of change of the distance between the two peopl, X and Y is given as

$\frac{dd^2}{dt} = \frac{dx^2}{dt} + \frac{dy^2}{dt}$

Therefore, $2d\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}$ or $d\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}$

Since $\frac{dx}{dt}$ is given as 2 ft/sec and $\frac{dy}{dt}$ = 7 ft/sec

Then $d\frac{dd}{dt} = 30 \times 2 + 105 \times 7 = 795\\$

$\frac{dd}{dt} = \frac{795}{109.202 } =7.28 ft/sec$

8 0

3 years ago

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A process engineer is implementing a quality assurance system on a breakfast cereal production line. A new sensor is installed o

nataly862011 [7]

Answer:

0.2%

Step-by-step explanation:

The given parameters are;

The percentage of product within the correct range = 95%

The percentage of the times the sensor reject boxes of incorrect weight = 98%

The percentage of the times the company reject boxes with correct weight = 1%

$\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}$

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776

The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%

The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

5 0

3 years ago