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uranmaximum [27]
3 years ago
9

What is the value of X

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

x = 12√2

Step-by-step explanation:

This is a right triangle, which makes things easier.  Both legs have length 12.

Using the Pythagorean Theorem, we get x^2 = 12^2 + 12^2, or 2(144).

Solving for x, we get x = 12√2.

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Two numbers are in the ratio of 4:9. If the larger number is 35 more than the smaller number, then product of the number is?
kherson [118]

Answer:

1764

Step-by-step explanation:

Let x = small number

Let y = large number

Form 2 equations

x/y=4/9

y=x+35

x/(x+35)=4/9

x=4/9x+4/9(35)

x-4/9x=140/9

5/9x=140/9

x=28

y=28+35

y=63

product of 2 numbers

28x63=1764

5 0
3 years ago
What is the best measure of the center for the data set: 2,2,2,4,4,5,5,5,7,7,15,17
VladimirAG [237]
5,5 are in the middle. So it is 5+5\2 which is 10\2 which is 5
7 0
3 years ago
What is the name of the two types of graph relationships?
GrogVix [38]

Answer:

Step-by-step explanation:The formal term to describe a straight line graph is linear, whether or not it goes through the origin, and the relationship between the two variables is called a linear relationship. Similarly, the relationship shown by a curved graph is called non-linear.

4 0
3 years ago
if <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B3%7D%20-%20%5Cfrac%7B1%7D%7B2%7Dx%20" id="TexFormula1" title="f
Dimas [21]

Answer:

\large\boxed{(f+g)(x)=2x^2+\dfrac{1}{2}x+4\dfrac{1}{3}}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\\text{We have}\\\\f(x)=\dfrac{1}{3}-\dfrac{1}{2}x,\ g(x)=2x^2+x+4.\\\\\text{Substitute:}\\\\(f+g)(x)=\left(\dfrac{1}{3}-\dfrac{1}{2}x\right)+(2x^2+x+4)\\\\=\dfrac{1}{3}-\dfrac{1}{2}x+2x^2+x+4\qquad\text{combine like terms}\\\\=2x^2+\left(-\dfrac{1}{2}x+x\right)+\left(\dfrac{1}{3}+4\right)\\\\=2x^2+\dfrac{1}{2}x+4\dfrac{1}{3}

6 0
3 years ago
Helpppp I’m marking brainliest
NeX [460]

Answer:

1.  Quadrant IV (4)

2. Quadrant I (1)

3. Quadrant II (2)

4. Quadrant II (2)

5. Quadrant III (3)

6. Quadrant 1 (1)

hope this helps!! :]

8 0
3 years ago
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