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4 years ago

How many times can 52 go into 8

2 answers:

5 0

52 can't go into 8, but 8 can go into 52. it goes into it 6 times, but not evenly it would essentially be a fraction. the decimal form is 6.5, so the fraction is 13/2 . the mixed number is 6 1/2

Gekata [30.6K]4 years ago

4 0

56 cant go into the number 8. 8 can go into 56, it can go 7 times

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A girl made a ladybug cage. Her cage has five sides. Each side has a length of 28 centimeters (cm). The cage is 20 cm high. What

Aleksandr [31]

The shape of her Cage's base is Pentagon

The perimeter of the base of the cage is 140 cm

Step-by-step explanation:

Side length of the base of the cage = 28cm

No. of sides the base has = 5

The shape of the cages base is Pentagon as it has 5 sides.

Perimeter= 5(28)

= 140cm

The perimeter of the base of the cage is 140 cm

5 0

3 years ago

a racecar at the sonoma county raceway in california zips around the track. it travels the first 80 kilometers in .4 hour. the n

Viktor [21]

$\\ \tt\longmapsto Avg\:Speed=\dfrac{Total\:Distance}{Total\:Time}$

$\\ \tt\longmapsto AVg\:Speed=\dfrac{80+114+80}{0.6+0.4+0.4}$

$\\ \tt\longmapsto Avg\:Speed=\dfrac{274}{1.4}$

$\\ \tt\longmapsto Avg\:Speed=195.7km/h$

4 0

3 years ago

Read 2 more answers

What is 987 × 765?<br><br> 21 points!!

In-s [12.5K]

The answer is 755,055.

3 0

3 years ago

Read 2 more answers

Please help if don't get passed this then I will be stuck on my classes again

alina1380 [7]

Answer:

A) y > -3×+1

Step-by-step explanation:

hope that helps

5 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago