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3 years ago

Question 5 (2 points)

Mathematics

1 answer:

Digiron [165]3 years ago

6 0

1600 bc if you use your calculator that’s what you get

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What is the graph to the rational function?

Aneli [31]

We are given

$y=\frac{x^2-4x+3}{x^2-9}$

Vertical asymptotes:

Firstly, we will factor numerator and denominator

we get

$y=\frac{(x-1)(x-3)}{(x-3)(x+3)}$

We can see that (x-3) is common in both numerator and denominator

so, we will only set x+3 to 0

and then we can find vertical asymptote

$x+3=0$

$x=-3$

Hole:

We can see that (x-3) is common in both numerator and denominator

so, hole will be at x-3=0

$x-3=0$

$x=3$

Horizontal asymptote:

We can see that degree of numerator is 2

degree of denominator is also 2

for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator

and we get

$y=\frac{1}{1}$

$y=1$

so, option-D............Answer

7 0

3 years ago

Petra is asked to color 6/6 of her grid. She must use 3 colors: blue, red ad pink. There must be more blue sections than red sec

Phoenix [80]

3 blue 2pink 1red or 3blue 2red 1pink

7 0

4 years ago

PLS someone help me im trying to get a 80% so i can finish this!

klasskru [66]

Answer:

any number less than 3

Step-by-step explanation:

3 0

3 years ago

For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to

Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$ are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. $\vec{A}\cdot \vec{B}=0$

Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$

$(i+j+kq)\cdot (iq-2j+2kq)=0$

$(1)(q)+(1)(-2)+(q)(2q)=0$

$q-2+2q^2=0$

$2q^2+q-2=0$

Using quadratic formula,

$q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}$

$q=\frac{-1\pm\sqrt{17}}{4}$

$q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}$

$q=0.781,-1.281$

Therefore, The value of q are 0.781,-1.281.

6 0

3 years ago

A motorcycle can travel 70 miles per gallon. Approximately how many gallons of fuel will the motorcycle need to travel 60 km?

cricket20 [7]

We have the following given
mileage = 70 miles per gallon
distance = 60 km

Required: amount of fuel in gallons

First, we must convert the distance to miles, so
60 km (1 mi/1.6 km) = 37.5 mi

So, the amount of fuel is
37.5 mi / (70 mi/gal) = 0.54 gallons

5 0

3 years ago

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