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sertanlavr [38]

3 years ago

9

Help with slope-intercept form

1 answer:

Tatiana [17]3 years ago

7 0

The answer is y=-5/2x+18

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Can 1/45 be simplified

Pani-rosa [81]

<span> - </span>1/45<span> = - </span>1/45 = - 0.022222222222 <span>Fraction </span>can<span>'t be reduced</span>

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15 - 7 + 3 ( 6 + 2) / 2^3 PLEASE SOLVE BY USING A STEP BY STEP SOLUTION

Slav-nsk [51]

Answer:

<h2>11</h2>

Step-by-step explanation:

PEMDAS

Parentheses first:

15 - 7 + 3 (8) / 2^3

Exponent second:

15 - 7 + 3 (8) / 8

Multiplication:

15 - 7 + 24 / 8

Division:

15 - 7 + 3

Addition:

15 - 4

Subtraction:

11

6 0

3 years ago

Match The Following, 26 POINTS HELP FAST

zavuch27 [327]

The formula for the volume of a cone is:

$1/3\pi r^{2} h$

The formula for the volume of a cylinder is:

$\pi r^2h$

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$bh$

The formula for the volume of a pyramid is:

$1/3bh$

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$lwh$

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3 years ago

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Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...

katovenus [111]

Answer:

$a_{12}=-244140625$

Step-by-step explanation:

Considering the geometric sequence

$5,-25,\:125,\:...$

$a_1=5$

As the common ratio ' $r$ ' between consecutive terms is constant.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$r=\frac{-25}{5}=-5$

$r=\frac{125}{-25}=-5$

The general term of a geometric sequence is given by the formula:

$a_n=a_1\cdot \:r^{n-1}$

where $a_1$ is the initial term and $r$ the common ratio.

Putting $n = 12$ , $r = -5$ and $a_1=5$ in the general term of a geometric sequence to determine the 12th term of the sequence.

$a_n=a_1\cdot \:r^{n-1}$

$a_n=5\left(-5\right)^{n-1}$

$a_{12}=5\left(-5\right)^{12-1}$

$=5\left(-5^{11}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-5\cdot \:5^{11}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=-5^{1+11}$ ∵ $5\cdot \:5^{11}=\:5^{1+11}$

$=-244140625$

Therefore,

$a_{12}=-244140625$

6 0

3 years ago