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Dvinal [7]
3 years ago
8

During a 1 mile race, one runner is running at a rate of 14.6 feet per second, and another runner is running at a rate of 11.3 f

eet per second. One lap around the track is 660 feet. After how many seconds will the faster runner be exactly one lap ahead of the other runner?
Mathematics
2 answers:
DerKrebs [107]3 years ago
7 0

Step-by-step explanation:

14.6-11.3=3.3

660/3.3= 200

he would be 200 seconds ahead

Vikki [24]3 years ago
6 0

Answer:

13.201 about maybe not precisely

Step-by-step explanation:

ur mom

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Answer:

tan(450-a)=5\sqrt{3}-8

Step-by-step explanation:

We know that:

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Remember:

450°=360°+60°

and:

tan(a)=\frac{1}{2}

Thus:

tan(450-a)=\frac{tan(60)-tan(a)}{1+tan(60)tan(a)}\\\\

Then:

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