1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katena32 [7]
4 years ago
10

A __________ is a device that allows a computer, which works with digital information, to communicate over lines that use analog

signals.
Computers and Technology
1 answer:
navik [9.2K]4 years ago
3 0

Answer:

MODEM(Modulator Demodulator)

Explanation:

A modem is a device used in data communication that allows analog signal to be sent over a telephone line.

The modem works by converting the analog signal into digital data that the computer understands. The digital data is converted back to its original form at the receiver end.

Modem modulates analog signal from a telephone line to digital data the computer can understand. also, at the receiver end, it demodulates the digital data back to its original analog signal.

You might be interested in
You can join tables by using a condition in the ____ clause.​
andre [41]
You can join tables by using a condition in the "where" clause.
4 0
4 years ago
Why might people feel differently about their digital lives?
denpristay [2]
Same reasons as why people feel differently toward real life. It depends on your activities on Internet, and the kind of environment you spent in it, mainly how other users interacted you.
7 0
3 years ago
A U.S. social security number consists of a string of 9 digits, such as "444422333". Declare a char array named ssn suitable for
tatuchka [14]

Answer:

Since the question expect us to declare a C-string, the solution code is written in C as follows:

  1.    char ssn[9];
  2.    scanf("%s",ssn);

Explanation:

A C-String is a string written in C language. It is an array of characters. To declare a C-string, we use the keyword, <em>char </em>and then followed with the variable name + brackets and the number of characters in the string. For example, we can create a C-String for the SSN number as in Line 1.

To read standard input into the array, we can use C built-in function, <em>scanf(). </em>Just include a string placeholder, %s, and the variable<em> ssn </em>as arguments to <em>scanf()</em>. This will assign the string input by user to variable <em>ssn</em> as C-String.

8 0
3 years ago
Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0
3 years ago
Suppose there are 69 packets entering a queue at the same time. Each packet is of size 7 MiB. The link transmission rate is 1.7
svp [43]

Answer:

69.08265412 milliseconds

Explanation:

Lets first convert 7 MiB to bits

7*1024*1024*8=58720256 bits

Now convert bits to Gbits

58720256/10^{9}  =0.058720256 Gbits

Queuing Delay = Total size/transmission link rate

Queuing Delay= \frac{0.058720256}{1.7} =0.03454132706 seconds

Delay of packet number 3 = 0.03454132706*2=0.06908265412 seconds

or 0.06908265412= 69.08265412 milliseconds

7 0
3 years ago
Other questions:
  • How do you ask someone for help?
    6·1 answer
  • If you implement a Wireless LAN (WLAN) to support connectivity for laptops in the Workstation Domain, which domain does WLAN fal
    5·1 answer
  • Rule- based systems are subset of expert systems true or false?
    7·1 answer
  • Help me find the difference between these logos
    10·2 answers
  • Several new projects are being staffed by outside contractors who will be working on servers in the contractors’ office, not in
    5·2 answers
  • Do you think LinkedIn stands to change the way employers hire? If so, how? Would this be a positive change or a negative one? Ex
    14·1 answer
  • Microsoft Access is a
    10·1 answer
  • Project Description:
    8·1 answer
  • Jason is the motion picture projectionist at the local IMAX theater. This means that he runs the huge movie projector so that cu
    12·1 answer
  • What is the purpose of quick access toolbar?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!