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sashaice [31]
2 years ago
11

How do you figure out if a number is divisible

Mathematics
1 answer:
Katarina [22]2 years ago
4 0

any number can be divisible but it might end up being a decimal.

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zzz [600]

\bf \textit{arc's length}\\\\ s=\cfrac{\pi \theta r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ \cline{1-1} \theta =135\\ r=11.4 \end{cases}\implies s=\cfrac{\pi (135)(11.4)}{180}\implies s=8.55\pi \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill s\approx 26.86~\hfill

3 0
3 years ago
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*BRAINIEST &amp; 20 POINTS*<br><br> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
kondor19780726 [428]

Answer:

8 = x

y = 29

Step-by-step explanation:

4x + 17 = y + 20 because vertical angles theorem.

y + 20 = 5x + 9  because interior angles theorem.

4x + 17 = 5x + 9  because same side interior angles theorem.

Subtract 9 from both sides and subtract 4x from both sides.

8 = x

Plug 8 in for x and solve.

5 times 8 is 40, plus 9 equals 49. Subtract 20 from both sides and you get 29.

5(8) + 9 = y + 20

49 = y + 20

29 = y

I hope this helps!

#teamtrees #WAP (Water And Plant)

5 0
2 years ago
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(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28
Veronika [31]

(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}

4 0
3 years ago
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Solve the quadratic equation by completing the square. x2 + 6x + 7 = 0
ruslelena [56]
Hello,

x²+2*3x+3²+7-9=0
==>(x+3)²-2=0
==>(x+3-√2)(x+3+√2)=0
==> x=-3+√2 or x=-3-√2
7 0
3 years ago
Decomposing to solve 527-139
mars1129 [50]

Answer:

388

Step-by-step explanation:

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3 years ago
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