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3 years ago

If m∠A = m∠B and m∠A + m∠C = ∠D, then m∠B + m∠C = ∠D.

Mathematics

2 answers:

Zina [86]3 years ago

3 0

Answer:

substitution property

Step-by-step explanation:

When you replace m∠A in the second equation with its equal, as defined by the first equation, you are making use of the substitution property.

That property says you can replace anything by its equal.

nekit [7.7K]3 years ago

3 0

Answer:

subsitution

Step-by-step explanation:

i jus took the quiz

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A pole that is 2.6 m tall casts a shadow that is 1.38 m long. At the same time, a nearby building casts a shadow that is 40.75 m

Lana71 [14]

Step-by-step explanation:

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PREALGEBRA

Melanie L. asked • 03/08/16

a pole that is 3.3m tall casts a shadow that is 1.78m long. at the same time, a nearby building casts a shoadow that is 49.75 m long. how tall is the building?

a pole that is 3.3m tall casts a shadow that is 1.78m long. at the same time, a nearby building casts a shoadow that is 49.75 m long. how tall is the building? Round to the nearest meter.

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Jane C. answered • 03/08/16

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Hi Melanie!

This problem involves proportion.

Let x be the unknown, which is the height of the building.

height of pole = height of the building

height of the shadow height of the shadow

3.3 m = x

1.78 m 49. 75 m

Solve for x.

(3.3 m) (49.75 m) = x

1.78 m

92.2331460674 = x

Rounded to the nearest meter, the building is 92 meters high.

Hope that helps.

The fraction bars are not coming out (Underline), I don't know why... but yeah, that is the answer.

8 0

3 years ago

At the movie theatre, child admission is $5.20 and adult admission is $9.00 . On Saturday, 156 tickets were sold for a total sal

stiks02 [169]

We can solve this by using systems of equations.

Let's find our first formula, how much money was made using the tickets.

$5.20x + 9y = 1027.80$

Here x is how many child tickets we sold and y is how many adult tickets we sold. Now that we have defined that, we can make another formula for the total tickets sold!

$x + y = 156$ since we sold 156 tickets that could be any combination of child and adult tickets.