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Murljashka [212]
3 years ago
5

Find an equation of the circle having the given center and radius. Center ( - 1, 1), radius 7

Mathematics
2 answers:
Alinara [238K]3 years ago
8 0

Answer:

(x+1)^2+(y-1)^2=49

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

where the center is (h,k) and r is the radius

so h=-1 and k=1 in this case

so then (x- -1)^2+(y-1)^2=7^2

(x+1)^2+(y-1)^2=49

suter [353]3 years ago
7 0

Answer:

(x+1)^2 + (y+1)^2 = 49

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x- -1)^2 + (y- -1)^2 = 7^2

Simplifying

(x+1)^2 + (y+1)^2 = 49

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A woman standing on a hill sees a flagpole that she knows is 65 ft tall. The angle of depression to the bottom of the pole is 14
Oliga [24]

Answer:

Let the distance between woman and pole be "x".

From diagram,

In ΔOAB,

tan 18 = \frac{Perpendicular}{Base}

tan 18 =  \frac{65 -y}{x}

∴ x =  \frac{65 -y}{tan 18} ................ (1)

In ΔOBC

tan 14 = \frac{Perpendicular}{Base}

tan 14 =  \frac{y}{x}

y = x × tan 14 ..............(2)

equating (2) in (1), we get;

x = \frac{65}{tan 18 + tan 14}

x = \frac{65}{0.574}

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3 years ago
(√0,04-√(-1,2)²+√121)×√81
Semenov [28]

Answer:  90

Step-by-step explanation:

\displaystyle\ \Large \boldsymbol{} (\sqrt{0,04}-\sqrt{(-1,2)^2}+\sqrt{121 } ) \cdot \sqrt{81} = \\\\\\(0,2-1,2+11)\cdot 9=(11-1)\cdot 9=90

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gayaneshka [121]

Here , the ratio <em><u>UV:</u></em><em><u>VW</u></em> and <em><u>UT:TS</u></em> will be in proportion , so ;

{:\implies \quad \sf \dfrac{UV}{VW}=\dfrac{UT}{TS}}

Putting the given values ;

{:\implies \quad \sf \dfrac{18}{36}=\dfrac{UT}{24}}

{:\implies \quad \sf UT=\dfrac{1}{2}\times 24}

{:\implies \quad \bf \therefore \quad \underline{\underline{UT=12 \:\: units}}}

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Answer:

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